获取同一列多行的总金额和总两个不同行（MySQL查询）

Question

我有一个表“记载”的 [记录] [1]

select typeofservice, 
     Coalesce(sum(incomecost,expensecost),0) 'incomecost,expensecost' 
from records 
where dateoftrans = '2016-11-22' 
group by typeofservice with rollup; 

我希望能够有在第二个图像上的结果，这是我的查询......所有这些交易发生在一天。请帮助

https://i.stack.imgur.com/fLYav.png

Answer 1

如果只对第二图像的结果，你可以尝试sum(incomecost)和sum(expensecost)这样的：

SELECT 
    typeofservice, 
    Coalesce(SUM(incomecost), 0) AS incomecost, 
    Coalesce(SUM(expensecost), 0) AS expensecost 
FROM records 
GROUP BY typeofservice 
WITH ROLLUP 

Answer 2

下面的查询假设，对于给定类型的服务，你希望在收入成本的总和超过费用成本的总和报告的收入，反之亦然。在每种情况下，收入和费用之间的差额报告在相应的栏中，NULL在备用栏中报告。

SELECT typeofservice, 
     CASE WHEN SUM(incomecost) - SUM(expensecost) > 0 
      THEN SUM(incomecost) - SUM(expensecost) 
      ELSE NULL END AS incomecost, 
     CASE WHEN SUM(expensecost) - SUM(incomecost) > 0 
      THEN SUM(expensecost) - SUM(incomecost) 
      ELSE NULL END AS expensecost 
FROM records 
WHERE dateoftrans = '2016-11-22' 
GROUP BY typeofservice 
WITH ROLLUP