2010-03-09 231 views
52

numpy.average()有一个权重选项,但numpy.std()没有。有没有人有解决方法的建议?NumPy中的加权标准偏差?

+0

顺便说一句,加权标准偏差计算实际上是一个相当复杂的课题 - 不止一种方法去做一件事。请参阅这里进行一次精彩的讨论:https://www.stata.com/support/faqs/statistics/weights-and-summary-statistics/ – JohnE 2017-11-18 17:09:47

回答

80

以下简短的“手动计算”如何?

def weighted_avg_and_std(values, weights): 
    """ 
    Return the weighted average and standard deviation. 

    values, weights -- Numpy ndarrays with the same shape. 
    """ 
    average = numpy.average(values, weights=weights) 
    # Fast and numerically precise: 
    variance = numpy.average((values-average)**2, weights=weights) 
    return (average, math.sqrt(variance)) 
+2

为什么不再为方差使用'numpy.average'? – user2357112 2013-08-07 01:26:29

+4

只是想指出,这会给偏差的方差。对于小样本量,您可能需要重新调整方差(在sqrt之前)以获得无偏差的方差。请参阅https://en.wikipedia.org/wiki/Weighted_variance#Weighted_sample_variance – Corey 2014-03-07 05:17:17

+1

是的,无偏差方差估计量会略有不同。这个答案给出了标准偏差,因为问题要求'numpy.std()'的加权版本。 – EOL 2014-09-12 09:58:19

6

在numpy/scipy中似乎还没有这样的功能,但是有一个ticket提出了这个附加功能。包括那里你会发现Statistics.py实施加权标准差。

13

有在statsmodels一个类来计算加权统计:statsmodels.stats.weightstats.DescrStatsW

from statsmodels.stats.weightstats import DescrStatsW 

array = np.array([1,2,1,2,1,2,1,3]) 
weights = np.ones_like(array) 
weights[3] = 100 

weighted_stats = DescrStatsW(array, weights=weights, ddof=0) 

weighted_stats.mean  # weighted mean of data (equivalent to np.average(array, weights=weights)) 
# 1.97196261682243 

weighted_stats.std  # standard deviation with default degrees of freedom correction 
# 0.21434289609681711 

weighted_stats.std_mean # standard deviation of weighted mean 
# 0.020818822467555047 

weighted_stats.var  # variance with default degrees of freedom correction 
# 0.045942877107170932 

这个类的很好的功能是,如果你想计算不同的统计特性随后调用将是非常快的,因为已经计算(甚至中间)的结果被缓存。

1

有由gaborous提出了一个很好的例子:

import pandas as pd 
import numpy as np 
# X is the dataset, as a Pandas' DataFrame 
mean = mean = np.ma.average(X, axis=0, weights=weights) # Computing the 
weighted sample mean (fast, efficient and precise) 

# Convert to a Pandas' Series (it's just aesthetic and more 
# ergonomic; no difference in computed values) 
mean = pd.Series(mean, index=list(X.keys())) 
xm = X-mean # xm = X diff to mean 
xm = xm.fillna(0) # fill NaN with 0 (because anyway a variance of 0 is 
just void, but at least it keeps the other covariance's values computed 
correctly)) 
sigma2 = 1./(w.sum()-1) * xm.mul(w, axis=0).T.dot(xm); # Compute the 
unbiased weighted sample covariance 

Correct equation for weighted unbiased sample covariance, URL (version: 2016-06-28)