如何编程Arduino忽略按下按钮后按下按钮5分钟？

Question

我正在使用一个按钮来触发一个继电器;代码如下。

我想编程我的Arduino忽略任何后续按下按钮5分钟的时间。我如何在我的Arduino草图中包含这个功能？

这样做的目的是禁止用户重复触发继电器，反复按下按钮直至间隔5分钟。这是用于公共艺术作品的，如下所示，需要施加这样的限制以保证作品的适当使用。

int pinButton = 8; 
int Relay = 2; 
int stateRelay = LOW; 
int stateButton; 
int previous = LOW; 
long time = 0; 
long debounce = 500; 
int stayON = 5000; //stay on for 5000 ms 

void setup() { 
    pinMode(pinButton, INPUT); 
    pinMode(Relay, OUTPUT); 
} 

void loop() { 
    stateButton = digitalRead(pinButton); 
    if(stateButton == HIGH && previous == LOW && millis() - time > debounce) { 
    if(stateRelay == HIGH){ 
     digitalWrite(Relay, LOW); 
    } else { 
     digitalWrite(Relay, HIGH); 
     delay(stayON); 
     digitalWrite(Relay, LOW); 
    } 
    time = millis(); 
    } 
    previous == stateButton; 
} 

Answer 1

您可以添加一个变量来存储上次显示被激活的时间。然后，您可以将您的else语句更改为elseif语句，在该语句中将当前运行时间与上次激活时间进行比较。这与您使用的去抖方法类似。

long lastActivated = 0; //last time display was activated 
long myDelay = 300000; //5 minutes in millis 


    if(stateButton == HIGH && previous == LOW && millis() - time > debounce) { 
    if(stateRelay == HIGH){ 
     digitalWrite(Relay, LOW); 
    } else if (millis() - lastActivated > myDelay) { //verifies it's been 5 minutes 
     digitalWrite(Relay, HIGH); 
     delay(stayON); 
     digitalWrite(Relay, LOW); 
     lastActivated = millis(); //resets lastActivated when display is allowed to activate 
    } 
    time = millis(); 
    }