挣扎在阵列返回记录正确

-1

function score(string,pattern) 
{ 
    var lowercasestring = string.toLowerCase(); 
    var lowercasepattern = pattern.toLowerCase(); 
    var patterncount = 0; 
    for(i=0;i<lowercasestring.length;i++) //For loop that cycles through each character in the string 
     if(i==lowercasestring.indexOf(lowercasepattern,i)) //If the pattern exists in the string past the current character it's on, add one to the patern count 
      patterncount++; 
    return(patterncount); 
} 

var web = [ {url : "www.lboro.ac.uk", content : "Loughborough University offers degree programmes and world class research." } , {url : "www.xyz.ac.uk", content : "An alternative University" } , {url : "www", content : "Yet another University" } ] 

function urlScores(web,pattern) 
{ 
    var array = []; 
    for(var i=0;i<=web.length-1;i++) 
    { 
     var record = {}; 
     record.url = web[i].url; 
     record.score = score(web[i].content,pattern); 
     if (record.score!=0) 
     { 
     array[i] = record; 
     } 
    } 
    return(array); 
} 

alert(urlScores(web,"University"));

当前标准的，在底部的警报只返回[对象对象]，[目标对象]，[目标对象]挣扎在阵列返回记录正确

提醒record.score和记录。 url给出了正确的值，但在它自己的警报[object Object]上提醒记录。因此array [i]被设置为记录，这就是返回的内容。我不确定如何将记录实际显示为{url：web [i] .url value score：score（web [i] .content，pattern value}（我试图将它放在没有值部分的位置如果我用console.log替换任何警报，它也会显示Object，这与如何使用.url和.dll有关。比分被插嘴说。

来源

2016-11-17 JReyn

嗨代码工作完美;如果将alert(urlScores(web,"University"));替换为console.table(urlScores(web,"University"));，控制台将显示所需的结果。

来源

2016-11-17 11:51:28 Laazo

我的意思是提醒价值，所以我只是做了一个arraytoreturn变量，然后在字符串形式的每个数组值中打印url和分数，但我将在以后记住这一点，但是当我了解console.table – JReyn

警报只是用于显示简单的字符串，请尝试使用控制台，你会看到它的工作..

function score(string,pattern) 
 
{ 
 
    var lowercasestring = string.toLowerCase(); 
 
    var lowercasepattern = pattern.toLowerCase(); 
 
    var patterncount = 0; 
 
    for(i=0;i<lowercasestring.length;i++) //For loop that cycles through each character in the string 
 
     if(i==lowercasestring.indexOf(lowercasepattern,i)) //If the pattern exists in the string past the current character it's on, add one to the patern count 
 
      patterncount++; 
 
    return(patterncount); 
 
} 
 

 
var web = [ {url : "www.lboro.ac.uk", content : "Loughborough University offers degree programmes and world class research." } , {url : "www.xyz.ac.uk", content : "An alternative University" } , {url : "www", content : "Yet another University" } ] 
 

 
function urlScores(web,pattern) 
 
{ 
 
    var array = []; 
 
    for(var i=0;i<=web.length-1;i++) 
 
    { 
 
     var record = {}; 
 
     record.url = web[i].url; 
 
     record.score = score(web[i].content,pattern); 
 
     if (record.score!=0) 
 
     { 
 
     array[i] = record; 
 
     } 
 
    } 
 
    return(array); 
 
} 
 

 
console.log(urlScores(web,"University"));

来源

2016-11-17 11:50:44 Keith

挣扎在阵列返回记录正确

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