PHP将数组移动到不同的文本文件中？

Question

我已经给出了一个数据列表，我需要将其拆分并将其移动到不同的文本文件中。到目前为止，我已经尝试了一些东西，但似乎无法使其发挥作用。

<?php 

/* 
*order the file based on surname (col 2) 
*create two new text files - class A and B 
*split the source text into two equal lists 
*format them: ID, firstname, lastname. all words must be first letter caps 
*move each list to a new file. 
*close files 
*/ 

//This function converts every attribute/variable passed to it into a sentence case 
function Uppercase($convert) { 
    return ucwords($convert); 
} 

//This function compares two items to see which one is higher 
//src: http://php.net/manual/en/function.usort.php 
function cmp($a, $b) { 
$compResult = strcmp($a[1], $b[1]); 

if ($compResult == 0) { 
    return strcmp($a[2], $b[2]); 
}else { 
    return $compResult; 
} 
} 

//This function gets rid of the whitespace that is not needed 
function cut($c) { 
    return trim($c, " \n\r\0"); 
} 

//open file 
$myfile = fopen("students.csv", "r"); 

echo "A"; 

//initialise the array, giving them 'headers' 
$array = array(); 

echo "B"; 

//sort through the data, moving it to a multidimentional array and setting the first letter in each item to uppercase 
$i=0; 

while(!feof($myfile)){ 
$line = fgets($myfile); 

$pieces = explode(",", $line); 
$array[$i][0] = $pieces[0]; 
$array[$i][1] = cut(Uppercase($pieces[2])); 
$array[$i][2] = cut(Uppercase($pieces[1])); 

$i++; 
} 

echo "C"; 

//sort the file by the second item in the array 
usort($array, "cmp"); 
echo array_shift($array)."<br>"; 

echo "D"; 

//create class files 
$fileA = fopen("Class 1.txt", "w"); 
$fileB = fopen("Class 2.txt", "w"); 

echo "E"; 

//get size of array 
$arraylength = count($array); 

//half the array length(
$half = ceil($arraylength /= 2); 
//echo $half; 

//echo $arraylength."</br>"; 
echo "F"; 

echo "<pre>"; 
print_r($array); 
echo "</br>"; 

//move the first class into a text file 
$k = 0; 

foreach ($array as $key){ 
    echo $key[0]; 

    if ($k < $half) { 
     $current = file_get_contents($fileA); 
     $current .= $key; 
    } 
} 

echo "G"; 

fclose($fileA); 
fclose($fileB); 
fclose($myfile); 

echo "H"; 

当该运行时，得到下面的行阵列

警告在重复针对每个项目：file_get_contents（）函数预计参数1是在C中给出的有效路径，资源：\ XAMPP \ htdocs中\ PHPLabs \ EE1600Assignment.php上线93

文件本身有25项是这样的：

123, billy, bobs 

任何帮助表示赞赏。谢谢

Answer 1

file_get_contents需要一个文件路径，但是您提供了一个文件处理程序。您可能需要fgets($fileA)。

或者，如果您想要读取完整文件（它不完全清楚您的代码），则可以使用fread($fileA)。

Answer 2

根据documentation，file_get_contents需要指向要打开的文件的路径（根据您收到的错误消息 - file_get_contents() expects parameter 1 to be a valid path）。

你传递$fileA - 您先前使用fopen的调用

fopen("Class 1.txt", "w");