2016-04-26 73 views
2

我使用slick 3.1,Play框架2.5和scala 2.11。我的应用程序有'用户'表,其中引用列'addressId'表示'地址'表的'id'列。我无法在这两个表中插入数据。下面是该如何使用scala在play-slick中编写包含引用列的表的插入查询到另一个表?

此代码的用户窗体:

val registerForm: Form[RegisterForm] = Form { 
mapping(
    "id" -> optional(number), 
    "firstname" -> nonEmptyText.verifying("letters only", name => name.isEmpty || name.matches("[A-z\\s]+")), 
    "lastname" -> nonEmptyText.verifying("letters only", name => name.isEmpty || name.matches("[A-z\\s]+")), 
    "email" -> text.verifying(nonEmpty), 
    "password" -> text.verifying(nonEmpty), 
    "address" -> mapping(
     "id" -> optional(number), 
     "city" -> nonEmptyText.verifying("letters only", name => name.isEmpty || name.matches("[A-z\\s]+")), 
     "state" -> text, 
     "country" -> text, 
     "pin" -> number 
    )(AddressForm.apply)(AddressForm.unapply) 
)(RegisterForm.apply)(RegisterForm.unapply) 
} 

这是两个模型类:

case class Address(id: Option[Int], city: String, state: String, country: String, pin: Int) 
case class User(id: Option[Int], firstname: String, lastname: String, email: String, password: String, addressId: Option[Int]) 

这里是映射到相应的数据库表与表查询两类:

private class UserDB(tag: Tag) extends Table[User](tag, "user") { 

def id = column[Option[Int]]("id", O.PrimaryKey, O.AutoInc) 

def firstname = column[String]("firstname") 

def lastname = column[String]("lastname") 

def email = column[String]("email") 

def password = column[String]("password") 

def addressId = column[Option[Int]]("address_id") 

override def * = (id, firstname, lastname, email, password, addressId) <> ((User.apply _).tupled, User.unapply) 

def address_fk= foreignKey("fk_user_address", addressId, addressTable)(_.id) 

} 

private class AddressDB(tag: Tag) extends Table[Address](tag, "address") { 

def id = column[Option[Int]]("id", O.PrimaryKey, O.AutoInc) 

def city = column[String]("city") 

def state = column[String]("state") 

def country = column[String]("country") 

def pin = column[Int]("pin") 

override def * = (id, city, state, country, pin) <> ((Address.apply _).tupled, Address.unapply) 

} 


private val userTable = TableQuery[UserDB] 

private val addressTable = TableQuery[AddressDB] 

请告诉我如何插入数据到两个相关的表使用光滑的查询。

非常感谢您提前。

回答

1

您应该使用ID返回的地址刀片和刀片在单个事务中用户表,例如:

val query = for { 
    adressId <- addressTable returning addressTable.map(_.id) += Address(....) 
    userTable += User(..., Some(adressId), ....) 
} yield() 

db.run(query.transactionally) 

编辑:上面的查询,如果你需要创建的用户,使用不返回任何东西,:

val query = for { 
    adressId <- addressTable returning addressTable.map(_.id) += Address(....) 
    user <- userTable returning userTable += User(..., Some(adressId), ....) 
} yield user 

db.run(query.transactionally) 
+0

非常感谢@HüseyinZengin,它的工作和解决了我的问题。 – Govardhan

+0

此查询返回单位。如果我希望它返回Future [User]? – Govardhan

+0

非常感谢@HüseyinZengin。 – Govardhan

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