如何仅替换字符串的未加引号的部分？

Question

我将如何最好地实现以下内容：

我想在PHP中找到并替换字符串中的值，除非它们使用单​​引号或双引号。

EG。

$string = 'The quoted words I would like to replace unless they are "part of a quoted string" '; 

$terms = array(
    'quoted' => 'replaced' 
); 

$find = array_keys($terms); 
$replace = array_values($terms);  
$content = str_replace($find, $replace, $string); 

echo $string; 

echo“d字符串应该返回：

'The replaced words I would like to replace unless they are "part of a quoted string" ' 

在此先感谢您的帮助。

Answer 1

您可以将字符串拆分为带引号或不带引号的部分，然后仅在未加引号的部分调用str_replace。下面是一个使用preg_split的示例：

$string = 'The quoted words I would like to replace unless they are "part of a quoted string" '; 
$parts = preg_split('/("[^"]*"|\'[^\']*\')/', $string, -1, PREG_SPLIT_DELIM_CAPTURE); 
for ($i = 0, $n = count($parts); $i < $n; $i += 2) { 
    $parts[$i] = str_replace(array_keys($terms), $terms, $parts[$i]); 
} 
$string = implode('', $parts);