给定的输入字符串,如“1,2,3..6..8,9..11”,我们必须把它转换成“1,2,3,4,5,6,7,8,9,10,11”。所以基本上我们必须填充由点提到的范围。以下是我的解决方案。有没有更好的方法来解决这个问题?我们可以进一步优化吗?
public class FlattenAString {
public static String flattenAString(String input) {
StringBuilder sbr = new StringBuilder("");
StringBuilder current = new StringBuilder("");
StringBuilder next = new StringBuilder("");
int i = 0;
while (i < input.length()) {
if (input.charAt(i) == '.') {
i = i + 2;
while (i != input.length() && input.charAt(i) != '.' && input.charAt(i) != ',') {
next.append(input.charAt(i));
i++;
}
int currentInt = Integer.parseInt(current.toString());
int nextInt = Integer.parseInt(next.toString());
appendFromCurrentTillPrevToNextInt(currentInt, nextInt, sbr);
current = next;
next = new StringBuilder("");
} else if (input.charAt(i) == ',') {
sbr.append(current);
sbr.append(',');
current = new StringBuilder("");
i++;
} else {
current.append(input.charAt(i));
i++;
}
}
sbr.append(current);
return sbr.toString();
}
private static void appendFromCurrentTillPrevToNextInt(int current, int val, StringBuilder sbr) {
for (int i = current; i < val; i++) {
sbr.append(i);
sbr.append(',');
}
}
}
对Code Review(https://codereview.stackexchange.com)来说这似乎是一个很好的问题。 –
如果给出'[1..n]'的所有数字都存在,那么我们不能只取第一个和最后一个数字,并填充它们之间的所有其他数字? – Oswald
@Oswald:这确实是最好的解决方案,因为没有缺失整数。谢谢 –