问题与异步和等待在C＃

Question

调用方法：

internal object ExecuteJob(RequestParam inputParam) 
{ 
    bool jobStatus = false; 
    var result = jobManager.ExecuteJob(inputParam); 
    // Code continues 

} 

调用方法：

public async Task<int> ExecuteJob(RequestParam param) 
{ 
    await Task.Run(() => 
    { 
     result = package.Execute(); 
     jobResult = (int)result; 
    }); 

    return jobResult; 
} 

一旦包得到完成，应该返回到调用方法，我们如何才能做到这一点？因为在里面等待，我不能像以下使用回报，

await Task.Run(() => 
{ 
    result = package.Execute(); 
    jobResult = (int)result; 
    if(result == ssisruntime.DTSExecResult.Success) 
     return jobResult; 
}); 

请别人帮忙。

Answer 1

也许是这样的：

internal async Task<object> ExecuteJobAsync(RequestParam inputParam) 
{ 
    bool jobStatus = false; 

    var result = await jobManager.ExecuteJob(inputParam); 
    // Code continues 
} 

public Task<int> ExecuteJob(RequestParam param) 
{ 
    return Task.Run<int>(() => 
    { 
     return (int)package.Execute(); 
    }); 
}