Ajax在这两种情况下运行

我确认了提交值并获得成功提醒后，我创建了一个输入框，但我也取消了取消按钮的成功？Ajax在这两种情况下运行

swal({ 
    title: " Asking price for " + askData[0] + "?", 
    text: "If you are sure press OK or edit this text", 
    type: "input", 
    inputType: "text", 
    inputValue: "Hello " + askData[1] + ", I am interested in buying your " + askData[0] + " of Variety :" + askData[3] + ". Please update the Price!", 
    showCancelButton: true, 
    closeOnConfirm: false, 
    showLoaderOnConfirm: true 
}, function (inputValue) { 
    if (inputValue === "") { 
     swal.showInputError("Please write something !"); 
     return false; 
    } 
    $.ajax({ 
     url: urlEnq, 
     type: "GET" 
    }); 
    $.ajax({ 
     url: 'saveUserMessage', 
     type: "POST", 
     data: { 
      fieldUserId: fieldUserId, 
      filedUserCompanyId: filedUserCompanyId, 
      message: inputValue 
     }, 

    }) 
     .done(function (data) { 
      swal("Done!", "Your message has been successfully sent.", "success"); 
     }) 
     .error(function (data) { 
      swal.showInputError("Please write something !"); 
     });

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2015-12-02 Kamlesh Bisht

什么是'inputValue'可变的，当您单击取消的价值？ –

inputValue用于输入值字段，一个文本框。 –

是的，我们知道变量的实际值是多少？你正在做一个如果在该变量，以决定是否需要做阿贾克斯调用 –

当使用SweetAlert传递到回调函数的变量的值将是false和不''被点击时取消。

我已经更新您的jsfiddle显示此，请参见下面的更新的代码：

$('button.delete-account').click(function (e) { 
    swal({ 
     title: "Are you sure you want to delete your account?", 
     text: "If you are sure, type in your password:", 
     type: "input", 
     inputType: "password", 
     showCancelButton: true, 
     closeOnConfirm: false 
    }, function (typedPassword) { 
     if (typedPassword === false) { 
      return; 
     } 
     if (typedPassword === "") { 
      swal.showInputError("You need to type in your password in order to do this!"); 
      return false; 
     } 
     $.ajax({ 
      url: "/api/delete-account", 
      data: { password: typedPassword }, 
      type: "POST" 
     }).done(function (data) { 
      swal("Deleted!", "Your account has been deleted!", "success"); 
     }).error(function (data) { 
      swal.showInputError("Your password is wrong!"); 
     }); 
    }); 
});

来源

2015-12-03 04:55:56

谢谢工作现在。 –

Ajax在这两种情况下运行

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