为什么的iOS 8.0模拟器在Xcode 6.0.1不能正确

升级后取cookie来的Xcode 6，当我从登录获取饼干“POST”行动，像这样：为什么的iOS 8.0模拟器在Xcode 6.0.1不能正确

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://%@/login.php", kDSZHDomainString]]; 
ASIFormDataRequest *asirequest = [ASIFormDataRequest requestWithURL:url]; 
[asirequest setPostValue:username forKey:@"u"]; 
[asirequest setPostValue:password forKey:@"p"]; 
[asirequest setTag:kLoginRequest]; 
[asirequest setStringEncoding:-2147481083]; 
[asirequest setTimeOutSeconds:600]; 
[asirequest setDelegate:self]; 
[asirequest startAsynchronous];

当我设置断点get请求的标题：

NSMutableDictionary * headers = [request requestHeaders];

调试信息：

Printing description of headers: 
{ 
    "Accept-Encoding" = gzip; 
    "Content-Length" = 20; 
    "Content-Type" = "application/x-www-form-urlencoded; charset=hz-gb-2312"; 
    Cookie = "__utma=213790228.284667840.1411460847.1411460847.1411460847.1; __utmz=213790228.1411460847.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); o=m; s=542366a13a44e; sv[1]=12532852%2C12532147%2C12534523; v[11]=12515374; v[1]=12534523; v[2]=12521992; v[3]=12527199; v[9]=12441637"; 
    "User-Agent" = "Top81 0.7 rv:0.7.459 (iPhone Simulator; iPhone OS 8.0; en_US)"; 
}

在iOS系统7模拟器，标题是：

Printing description of headers: 
{ 
    "Accept-Encoding" = gzip; 
    Cookie = "o=m; s=542369d4ede78; sv[1]=12532886%2C12528442%2C12534551; u=xxxx%2Ca999b1c0d3663e236f58277302b8be90%2C0; v[1]=12534551"; 
    "User-Agent" = "Top81 0.7 rv:0.7.459 (iPhone Simulator; iPhone OS 7.1; en_US)"; 
}

所以，cookie“u”正确提取。

我用ASIHTTPRequest和AFNetworking测试代码，并得到相同的结果。

它是Xcode和iOS 8模拟器的错误或任何代码来解决这个问题？

来源

2014-09-25 smoothdvd

我用afnetworking，它是在IOS 8 做工精细这里的功能

+(void)postData : (NSString *)url parameters:(NSDictionary *)paraDict success: (void (^) (NSDictionary *responseStr))success failure: (void (^) (NSError *error))failure 
{ 
    AFHTTPRequestOperationManager *manager = [[AFHTTPRequestOperationManager alloc] initWithBaseURL:[NSURL URLWithString:url]]; 

    manager.responseSerializer = [AFHTTPResponseSerializer serializer]; 

    AFHTTPRequestOperation *op = [manager POST:url parameters:paraDict constructingBodyWithBlock:^(id<AFMultipartFormData> formData) { 

    } success:^(AFHTTPRequestOperation *operation, id responseObject) 
    { 
     NSError* error = nil; 


     success([NSJSONSerialization JSONObjectWithData:responseObject options:0 error:&error]); 

    } failure:^(AFHTTPRequestOperation *operation, NSError *error) { 

     failure(error); 
    }]; 
    [op start]; 

}

这里输入的网址字符串不NSURL这应该是像@“http://www.google.com”

和paradict是字典.U可以使它像

的NSDictionary * paraDict = @ {@ “用户名”：@ “U”，@ “密码”：@ “p”}

希望它帮助

来源

2014-09-29 13:41:58 va05

为什么的iOS 8.0模拟器在Xcode 6.0.1不能正确

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