我正在使用履带。通常,当我在浏览器中输入url1时,浏览器将其转换为url2。 我如何在Python中做到这一点?转换履带的网址
URL1:www.odevsitesi.com/ara.asp?kelime=doğanındengesininbozulması
URL2:www.odevsitesi.com/ara.asp?kelime=do%F0an%FDn%20dengesinin%20bozulmas%FD
我正在使用履带。通常,当我在浏览器中输入url1时,浏览器将其转换为url2。 我如何在Python中做到这一点?转换履带的网址
URL1:www.odevsitesi.com/ara.asp?kelime=doğanındengesininbozulması
URL2:www.odevsitesi.com/ara.asp?kelime=do%F0an%FDn%20dengesinin%20bozulmas%FD
您需要对URL进行正确编码(在您的案例中为iso-8859-9),将它分成几部分,urllib.quote查询部分,然后重新组合。 I.e .:
>>> import urlparse
>>> import urllib
>>> x = u'http://www.odevsitesi.com/ara.asp?kelime=doğanın dengesinin bozulması'
>>> y = x.encode('iso-8859-9')
>>> # just to show what the split of y looks like (we can also handle it as a tuple):
>>> urlparse.urlsplit(y)
SplitResult(scheme='http', netloc='www.odevsitesi.com', path='/ara.asp', query='kelime=do\xf0an\xfdn dengesinin bozulmas\xfd', fragment='')
>>> z = urlparse.urlsplit(y)
>>> quoted = z[:3] + (urllib.quote(z.query), z.fragment)
>>> # now just to show you what the 'quoted' tuple looks like:
>>> quoted
('http', 'www.odevsitesi.com', '/ara.asp', 'kelime%3Ddo%F0an%FDn%20dengesinin%20bozulmas%FD', '')
>>> # and finally putting it back together:
>>> urlparse.urlunsplit(quoted)
'http://www.odevsitesi.com/ara.asp?kelime%3Ddo%F0an%FDn%20dengesinin%20bozulmas%FD'
urllib.quote
http://docs.python.org/library/urllib.html#urllib.quote
实施例:quote('/~connolly/')
产量'/%7econnolly/'
。
谢谢你的回答。 但这不适合我。 >>> urllib.quote(“www.odevsitesi.com/ara.asp?kelime=doğanındengesininbozulması”) >>>'www.odevsitesi.com/ara.asp%3Fkelime%3Ddo%F0an%FDn% 20dengesinin%20bozulmas%FD' – user260223 2010-06-14 17:34:09
只要确保你没有使用unicode,哪个urllib在Python 3之前不支持的那个urllib – danben 2010-06-14 17:36:40
@ user260223:你只想对url查询字符串进行url编码,而不是整个url – danben 2010-06-14 17:37:12