所以,我有这样的代码似乎并不工作:(更多详情如下)升压线程不会增加值正确
#include <boost/thread.hpp>
#include <boost/bind.hpp>
#include <Windows.h>
using namespace std;
boost::mutex m1,m2;
void * incr1(int thr, int& count) {
for (;;) {
m1.lock();
++count;
cout << "Thread " << thr << " increased COUNT to: " << count << endl;
m1.unlock();
//Sleep(100);
if (count == 10) {
break;
}
}
return NULL;
}
int main() {
int count = 0;
boost::thread th1(boost::bind(incr1,1,count));
boost::thread th2(boost::bind(incr1,2,count));
th1.join();
th2.join();
system("pause");
return 0;
}
基本上,它有一个函数有两个参数:一个数字(区分哪个线程调用它)和通过引用传递的整数变量“count”。 这个想法是,每个线程都应该在运行时增加计数值。 然而,结果是增加了自己的计数的版本,所以其结果是:
Thread 1 increased count to 1
Thread 2 increased count to 1
Thread 1 increased count to 2
Thread 2 increased count to 2
Thread 1 increased count to 3
Thread 2 increased count to 3
而不是每个线程增加数到下一个数字:
Thread 1 increased count to 1
Thread 2 increased count to 2
Thread 1 increased count to 3
Thread 2 increased count to 4
Thread 1 increased count to 5
Thread 2 increased count to 6
如果我运行此代码由简单地调用这个函数两次,它按预期工作。如果我使用线程,它不会。
完整的初学者在这里。任何洞悉我为什么愚蠢?
工作!谢谢。 – 2013-03-05 16:26:27