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这里是我的插入查询,我怎么能告诉,created_at
(当前时间戳),is_active
(默认1)在需要采取的mysql数据库结构中设置。Doctrine2不想插入表中的列
当我在插入操作省略$question->setCreatedAt($this->createdAt);
它显示我的完整性约束违规,你知道是什么问题?
在问题表:
question:
id
question
created_by
created_at
modified_by
modified_at
is_Active
实体:
<?php
namespace Library\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Base class for all the Entities
* This class maps id, active, created and modified columns
*
* @author
*/
/**
* @ORM\MappedSuperclass
*/
class BaseEntity {
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(name="id", type="integer")
* @var integer
*/
protected $id;
/**
* @ORM\Column(name="is_active", type="boolean")
* @var boolean
*/
protected $active;
/**
* @ORM\Column(name="created_at", type="datetime")
* @var datetime
*/
protected $createdAt;
/**
* @ORM\Column(name="created_by", type="integer", nullable=true)
* @var integer
*/
protected $createdBy;
/**
* @ORM\Column(name="modified_at", type="datetime")
* @var datetime
*/
protected $modifiedAt;
/**
* @ORM\Column(name="modified_by", type="integer")
* @var integer
*/
protected $modifiedBy;
public function getId() {
return $this->id;
}
public function getActive() {
return $this->active;
}
public function getCreatedAt() {
return $this->createdAt;
}
public function getCreatedBy() {
return $this->createdBy;
}
public function getModifiedAt() {
return $this->modifiedAt;
}
public function getModifiedBy() {
return $this->modifiedBy;
}
public function setId($id) {
$this->id = $id;
}
public function setActive($active) {
$this->active = $active;
}
public function setCreatedAt($createdAt) {
$this->createdAt = $createdAt;
}
public function setCreatedBy($createdBy) {
$this->createdBy = $createdBy;
}
public function setModifiedAt($modifiedAt) {
$this->modifiedAt = $modifiedAt;
}
public function setModifiedBy($modifiedBy) {
$this->modifiedBy = $modifiedBy;
}
}
这是我Question
实体:
<?php
namespace Survey\Entity;
use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\ORM\Mapping as ORM;
use Library\Entity\BaseEntity;
use Survey\Entity\Survey;
/**
* Description of Survey Questions
*
* @author Mubarak
*/
/**
* @ORM\Entity
* @ORM\Table(name="survey_questions")
*/
class Question extends BaseEntity{
/**
* @ORM\Column(name="question", type="string")
* @var string
*/
protected $question;
/**
* @ORM\ManyToOne(targetEntity="Survey\Entity\Survey", inversedBy="questions")
* @ORM\JoinColumn(name="survey_id", referencedColumnName="id")
*/
private $surveys;
public function getQuestion() {
return $this->question;
}
public function setQuestion($question) {
$this->question = $question;
}
public function getSurveys() {
return $this->surveys;
}
// public function setSurveys(ArrayCollection $survey) {
public function setSurveys(Survey $surveys = null) {
$this->surveys = $surveys;
}
// public function __toString() {
// return __CLASS__ . ": [id: {$this->id}, name: {$this->name}]";
// }
}
这里是我的插入OPERAT离子:
public function insertQuestion($userId, $survey, $questionArr) {
try{
$question = new Question();
$question->setQuestion($questionArr['question']);
$question->setSurveys($survey);
$question->setActive(1);
$question->setCreatedBy($userId);
$question->setCreatedAt($this->createdAt);
$question->setModifiedBy($userId);
$question->setModifiedAt($this->modifiedAt);
$this->entityManager->persist($question);
$this->entityManager->flush();
return $question;
}catch(Exception $ex){
throw new Exception("Couldnt insert the question");
}
}
这是好的,它的正常工作,但我不希望插入Created_at,modified_at
public function insertQuestion($userId, $survey, $questionArr) {
try{
$question = new Question();
$question->setQuestion($questionArr['question']);
$question->setSurveys($survey);
$question->setActive(1);
$question->setCreatedBy($userId);
$question->setModifiedBy($userId);
$this->entityManager->persist($question);
$this->entityManager->flush();
return $question;
}catch(Exception $ex){
throw new Exception("Couldnt insert the question");
}
}
谢谢,关于积极的情况下,你是对的,但created_at不工作 – user3929758
@ user3929758好吧。我从我的答案中删除了'created_at'部分。你应该认真检查出学说扩展名... – Wilt
它是格迪莫学说扩展库是Doctrine2的一个包装 – user3929758