限制与JOIN使用Zend框架

Question

我有2个表parent,children与关系1：M。我需要分页。我通过JOIN使用SELECT。对于1名父母，我有一些孩子。如果我试图使LIMIT 10这个查询总共得到10行。但我需要从表parent只有10行与所有关系。我该怎么做？
对不起，我的英语。先谢谢你。

MySQL查询：

SELECT `o`.`id` AS `order_id`, `od`.`id` AS `order_destination_id` FROM `order` AS `o` 
LEFT JOIN `order_destination` AS `od` ON o.id = od.order_id LIMIT 5 

Zend框架：

$select = $this->select() 
    ->setIntegrityCheck(false) 
    ->from(array('o' => 'order'), array('order_id' => 'id')) 
    ->joinLeft(array('od' => 'order_destination'), 'o.id = od.order_id', array('order_destination_id' => 'id')) 
    ->limit(5); 

Answer 1

我不知道了Zend框架。这里一个普通的SQL解决方案：

SELECT `o`.`id` AS `order_id`, `od`.`id` AS `order_destination_id` FROM `order` AS `o` 
LEFT JOIN `order_destination` AS `od` ON o.id = od.order_id 
where (select count(*) from order o2 where o2.id > o.id) < 10 

Answer 2

这是更好地使用Zend_Paginator的通过一个表进行分页，然后要求孩子每一个项目：

$paginator = Zend_Paginator::factory($this->select(), 'DbTableSelect'); 
$paginator->setItemsCountPerPage(5); 
foreach ($paginator as $row) { 
    $children = $row->getDependentRowset('ChildrenRule'); 
}