2014-09-13 152 views
0

我得到这个对象使用HttpGet请求,我想添加到具有更多对象的ArrayList。解析整个对象的正确方法是什么将它添加到数组中?将整个JSON对象添加到ArrayList

{ 
    "serial_number": "446D57D42F38", 
    "name": "Garage Door", 
    "accessories": [ 
    { 
     "obfuscated": false, 
     "target_state": "closed", 
     "current_state": "opening", 
     "name": "Garage Door Opener", 
     "locked": false 
    }, 
    { 
     "hue": 55.5, 
     "saturation": 85.5, 
     "name": "Light Bulb", 
     "power": true, 
     "brightness": 95 
    } 
    ] 
} 

代码:

List<String> accessories = new ArrayList<String>(); 

HttpResponse response = client.execute(httpGet); 
HttpEntity entity = response.getEntity(); 
InputStream content = entity.getContent(); 
InputStreamReader text = new InputStreamReader(content, "UTF-8"); 
accessories.add(text.toString()) 
+0

为什么不使用jsonarray?你可以使用EntityUtils获取字符串-json directlty – Nikhil 2014-09-13 14:41:06

+0

@Nikhil我在上面,谢谢你提供的信息! – Kenny 2014-09-13 14:47:15

回答

3

构造一个JSONArray,然后创建一个for循环。调用循环内的jsonarray内的对象。