我建议用更名的属性重建你的JSON。我不认为你应该担心速度处罚,因为这通常不是问题。这是你如何做到的。
public static JToken Rename(JToken json, Dictionary<string, string> map)
{
return Rename(json, name => map.ContainsKey(name) ? map[name] : name);
}
public static JToken Rename(JToken json, Func<string, string> map)
{
JProperty prop = json as JProperty;
if (prop != null)
{
return new JProperty(map(prop.Name), Rename(prop.Value, map));
}
JArray arr = json as JArray;
if (arr != null)
{
var cont = arr.Select(el => Rename(el, map));
return new JArray(cont);
}
JObject o = json as JObject;
if (o != null)
{
var cont = o.Properties().Select(el => Rename(el, map));
return new JObject(cont);
}
return json;
}
下面是使用的例子:
var s = @"{ ""A"": { ""B"": 1, ""Test"": ""123"", ""C"": { ""Test"": [ ""1"", ""2"", ""3"" ] } } }";
var json = JObject.Parse(s);
var renamed = Rename(json, name => name == "Test" ? "TestRenamed" : name);
renamed.ToString().Dump(); // LINQPad output
var dict = new Dictionary<string, string> { { "Test", "TestRenamed"} };
var renamedDict = Rename(json, dict);
renamedDict.ToString().Dump(); // LINQPad output
梅德感谢,这是完美的! – 2012-07-27 21:26:54
可以有一些小错误,但你可以自己修复它们,如果你发现任何:) – 2012-07-28 10:37:23