mysql select count另一个选择计数

Question

如何将这两个查询结合在mysql中？

select count(*) as entry_count from tbl_entries where user_id = x 

和

select username, avatar from tbl_users where user_id = x 

我想要一个结果，结合这2个查询的结果。请帮助我们！

谢谢！

Answer 1

select username, 
     avatar, 
     (select count(*) from tbl_entries where user_id = x) as entry_count 
from tbl_users 
where user_id = x 

Answer 2

select username, 
     avatar, 
     (select count(*) from tbl_entries where user_id = x) AS cnt 
    from tbl_users 
where user_id = x 

Answer 3

试试这个：

SELECT a.username, 
     a.avatar, 
     COUNT(*) as entry_count, 
FROM tbl_Users a LEFT JOIN tbl_entries b ON 
     a.user_ID = b.user_ID 
WHERE a.user_ID = x 
GROUP BY a.username 

Answer 4

试试这个：

SELECT U.username, U.avatar, 
    count(*) AS entry_count 
FROM tbl_users AS U 
LEFT JOIN tbl_entries AS E ON U.user_id = E.user_id 
WHERE user_id = x 
GROUP BY U.user_id; 

Answer 5

SELECT用户名， 头像， （SELECT COUNT（*）从tbl_entries其中USER_ID = U .user_id）AS cnt FROM tbl_users AS U WHERE user_id = x