PHP从表单到php传递变量

Question

我更像是一名前端开发人员，所以后端的东西有时会让我感到困惑。

我已经复制了现有网站的一些代码，但它在新网站上没有按预期运行。

我在使用酒店预订小部件。主页上有一个用于输入入住和退房日期的表格。点击提交按钮后，表单链接到所有可用房间的可用性表。

在当前网站上，表单上输入的日期被传递给可用性表。但是，当我复制代码时，它不再像那样起作用。我错过了什么？

这里是表单代码：

<script type="text/javascript"> 

jQuery(document).ready(function() { 
    jQuery('.MyDate1').datepicker({ 
     dateFormat : 'dd/mm/yy' 
    }); 

jQuery(document).ready(function() { 
    jQuery('.MyDate2').datepicker({ 
     dateFormat : 'dd/mm/yy' 
minDate: 0, 
onSelect: function(date){ 
var date2 = $('.MyDate2').datepicker('getDate'); 
      date2.setDate(date2.getDate()+1); 
      $('.MyDate1').datepicker('setDate', date2); 
    }); 

</script> 

<?php 
// ================================================== 
// Displays the Booking Panel Date selection options. 
// ================================================== 

// Set up some default Check-in/Check-out Dates. 
$checkinToday = date('d/m/Y'); 
$checkoutTomorrow = mktime(0, 0, 0, date('m'), date('d')+1, date('Y')); 
$checkoutTomorrow = date('d/m/Y', $checkoutTomorrow); 
?> 
       <form name="bookingform" action="https://www.clarionsuitesgateway.com.au/clarionhotel/booking-system/" method="post"> 
       <div class="booking-h3">Check Availability</div> 
       <div class="booking-row"> 
       <div class="booking-label">Check In Date</div> 
       <div class="booking-field"><input name="frmCheckin" id="frmCheckin" type="text" class="MyDate1" value="<?php echo $checkinToday; ?>" style="width:100%" /></div> 
       </div> 
       <div class="booking-row"> 
       <div class="booking-label">Check Out Date</div> 
       <div class="booking-field"><input name="frmCheckout" id="frmCheckout" type="text" class="MyDate2" value="<?php echo $checkoutTomorrow; ?>" style="width:100%" /></div> 
       </div> 
       <div class="booking-row"> 
       <div class="booking-row-box"> 
        <div class="booking-label">Adults</div> 
        <div class="booking-field"> 
         <select id="frmAdults" name="frmAdults"> 
         <?php for ($i = 1; $i <= 10; $i++): ?> 
            <option value="<?php echo $i; ?>"><?php echo $i; ?></option> 
         <?php endfor; ?> 
         </select>    
        </div> 
       </div> 
       <div class="booking-row-box"> 
        <div class="booking-label">Children</div> 
        <div class="booking-field"> 
         <select id="frmChildren" name="frmChildren"> 
         <?php for ($i = 0; $i <= 10; $i++): ?> 
            <option value="<?php echo $i; ?>"><?php echo $i; ?></option> 
         <?php endfor; ?> 
         </select>    
        </div> 
       </div> 
       <br clear="all"> 
       </div> 
       <div class="booking-row"> 
       <div class="booking-button"> 
        <input type="submit" value="Check Availability" name="Send" alt="Check Availability" /> 
        <input type="hidden" name="Submit" /> 
       </div> 
       </div>    
       </form> 

这里是它引导到可用性表：

<?php 
// ================================================== 
// BOOKING BUTTON specific page. 
// ================================================== 
// Set some default dates incase nothing is selected (we're not doing any error checking for this). 
// Today 
$CheckinDay = date('d'); 
$CheckinMonth = date('m'); 
$CheckinYear = date('Y'); 
// Tomorrow 
$CurrentDate = date('Y/m/d'); 
$Tomorrow = strtotime('+1 day', strtotime($CurrentDate)) ; 
$Tomorrow = date('d/m/Y', $Tomorrow); 
$arrCheckoutDate = explode("/", $Tomorrow); 
$CheckoutDay = $arrCheckoutDate[0]; 
$CheckoutMonth = date("M", mktime(0, 0, 0, $arrCheckoutDate[1], 1, 2012)); 
$CheckoutYear = $arrCheckoutDate[2]; 

$NumberAdults = 1; 
$NumberChildren = 0; 

if (isset($_POST["Submit"])) 
{ 
    if (strlen($_POST['frmCheckin'])) 
    { 
     $arrCheckinDate = explode("/", $_POST['frmCheckin']); 
     $CheckinDay = $arrCheckinDate[0]; 
     $CheckinMonth = date("M", mktime(0, 0, 0, $arrCheckinDate[1], 1, 2012)); 
     $CheckinYear = $arrCheckinDate[2]; 
    } 
    if (strlen($_POST['frmCheckout'])) 
    { 
     $arrCheckoutDate = explode("/", $_POST['frmCheckout']); 
     $CheckoutDay = $arrCheckoutDate[0]; 
     $CheckoutMonth = date("M", mktime(0, 0, 0, $arrCheckoutDate[1], 1, 2012)); 
     $CheckoutYear = $arrCheckoutDate[2]; 
    } 
    $NumberAdults = $_POST['frmAdults']; 
    $NumberChildren = $_POST['frmChildren']; 
} 
?> 
<?php get_header(); ?> 
<div id="ContentOuterContainer"> 
    <div id="ContentInnerContainerBookings"> 
     <?php while (have_posts()) : the_post(); ?> 

       <iframe src="https://www.thebookingbutton.com.au/xxx/properties/xxx?utf8=%E2%9C%93&locale=en&check_in_date=<?php echo $CheckinDay;?>+<?php echo $CheckinMonth;?>+<?php echo $CheckinYear;?>&check_out_date=<?php echo $CheckoutDay;?>+<?php echo $CheckoutMonth;?>+<?php echo $CheckoutYear;?>&number_adults=<?php echo $NumberAdults; ?>&number_children=<?php echo $NumberChildren; ?>&commit=Check+Availability" height="590" width="1047" frameborder="0" scrolling="yes" allowtransparency="true"></iframe> 


     <?php endwhile; ?> 
    <div class="clear"></div> 
    </div> 
</div> 
<div class="gap"></div> 
<?php get_footer(); ?> 

当我直接的形式向现有的可用性表，日期被通过。但是，当我将可用性表复制到新网站时，它会停止通过日期。任何想法我失踪？

谢谢！

Answer 1

它可能与'新'网站的表格上的字段有关。检查以确保它们是正确的数据类型。你在使用MySQL吗？我的猜测是，您可能无法正确连接到数据库。如果它在本地服务器上工作，但不会将任何数据放入新的服务器表中，那么PHP或Javascript可能没有任何问题。看看你的数据库。