我得到了一个要求,我有一个c文件,并且我正在生成LLVM IR。从生成的每个指令LLVM IR我计算需要执行多少个周期,现在我的问题是如何追溯到相同的C代码,并显示特定的C代码块(说功能)花了计算数量的周期(我实际上是从生成的LLVM IR代码计算的)。如何将C函数映射到LLVM IR?
我有如下交流代码:
int arithmeticOperations(int x, int y)
{
int aa, ab, ac, ad;
if(x>10)
{
aa = x+y;
ab = x-y;
for(x = 1; x <= aa; ++x)
{
y += x;
}
}
else
{
ac = x*y;
ad = x/y;
}
return aa * ab * ac * ad;
}
void arithmeticOperationsPart2(int x, int y)
{
int aa, ab, ac, ad;
if(x>10)
{
aa = x+y;
ab = x-y;
}
else
{
ac = x*y;
ad = x/y;
}
}
int main()
{
arithmeticOperations(35, 7);
arithmeticOperationsPart2(35, 7);
}
我使用命令创建LLVM IR:
clang -Os -S -emit-llvm addition.c
这个输出addition.ll文件,如下:
; ModuleID = 'addition.c'
source_filename = "addition.c"
target datalayout = "e-m:w-i64:64-f80:128-n8:16:32:64-S128"
target triple = "x86_64-pc-windows-msvc18.0.0"
; Function Attrs: norecurse nounwind optsize readnone uwtable
define i32 @arithmeticOperations(i32, i32) local_unnamed_addr #0 {
%3 = icmp sgt i32 %0, 10
br i1 %3, label %4, label %7
; <label>:4: ; preds = %2
%5 = add nsw i32 %1, %0
%6 = sub nsw i32 %0, %1
br label %10
; <label>:7: ; preds = %2
%8 = mul nsw i32 %1, %0
%9 = sdiv i32 %0, %1
br label %10
; <label>:10: ; preds = %4, %7
%11 = phi i32 [ undef, %7 ], [ %5, %4 ]
%12 = phi i32 [ undef, %7 ], [ %6, %4 ]
%13 = phi i32 [ %8, %7 ], [ undef, %4 ]
%14 = phi i32 [ %9, %7 ], [ undef, %4 ]
%15 = mul nsw i32 %12, %11
%16 = mul nsw i32 %15, %13
%17 = mul nsw i32 %16, %14
ret i32 %17
}
; Function Attrs: norecurse nounwind optsize readnone uwtable
define void @arithmeticOperationsPart2(i32, i32) local_unnamed_addr #0 {
ret void
}
; Function Attrs: norecurse nounwind optsize readnone uwtable
define i32 @main() local_unnamed_addr #0 {
ret i32 0
}
attributes #0 = { norecurse nounwind optsize readnone uwtable "correctly-rounded-divide-sqrt-fp-math"="false" "disable-tail-calls"="false" "less-precise-fpmad"="false" "no-frame-pointer-elim"="false" "no-infs-fp-math"="false" "no-jump-tables"="false" "no-nans-fp-math"="false" "no-signed-zeros-fp-math"="false" "no-trapping-math"="false" "stack-protector-buffer-size"="8" "target-cpu"="x86-64" "target-features"="+fxsr,+mmx,+sse,+sse2,+x87" "unsafe-fp-math"="false" "use-soft-float"="false" }
!llvm.module.flags = !{!0}
!llvm.ident = !{!1}
!0 = !{i32 1, !"PIC Level", i32 2}
!1 = !{!"clang version 5.0.0 (trunk 302984) (llvm/trunk 302983)"}
现在我想过滤LLVM代码与它生成的c源代码的对应关系(特定于某个函数)
例如(目前我要筛选的c函数arithmeticOperations
):
%3 = icmp sgt i32 %0, 10
br i1 %3, label %4, label %7
; <label>:4: ; preds = %2
%5 = add nsw i32 %1, %0
%6 = sub nsw i32 %0, %1
br label %10
; <label>:7: ; preds = %2
%8 = mul nsw i32 %1, %0
%9 = sdiv i32 %0, %1
br label %10
; <label>:10: ; preds = %4, %7
%11 = phi i32 [ undef, %7 ], [ %5, %4 ]
%12 = phi i32 [ undef, %7 ], [ %6, %4 ]
%13 = phi i32 [ %8, %7 ], [ undef, %4 ]
%14 = phi i32 [ %9, %7 ], [ undef, %4 ]
%15 = mul nsw i32 %12, %11
%16 = mul nsw i32 %15, %13
%17 = mul nsw i32 %16, %14
ret i32 %17
对应于C代码的以下部分:
int aa, ab, ac, ad;
if(x>10)
{
aa = x+y;
ab = x-y;
for(x = 1; x <= aa; ++x)
{
y += x;
}
}
else
{
ac = x*y;
ad = x/y;
}
return aa * ab * ac * ad;
为什么不从C或LLVM IR生成汇编列表文件,并自动获得平台架构的指令计数? –
@FrankC:感谢您的回复,我没有完全理解,LLVM IR生成的指令计数对于所有目标都是通用的吗? –
当您从LLVM-IR生成汇编程序列表时,指令集将是平台体系结构特定的。 –