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<?php
function saveFile($url, $filename) {
$data = file_get_contents($url);
$fh = fopen($filename, 'w') or die("can't open file");
fwrite($fh, $data);
fclose($fh);
}
$myFile = "images.txt";
$fh = fopen($myFile, 'r');
$theData = fread($fh, filesize($myFile));
$data = explode("\n", $theData);
$count = count($data);
for($i=0;$i<=$count;$i++) {
saveFile($data[$i], basename($data[$i]));
}
?>
这是我的代码我每次更换打印错误PHP下载文件,读取问题
Warning: fopen(10017226314.jpg) [function.fopen]: failed to open stream: Invalid argument in C:\xampp\htdocs\download\download.php on line 4
can't open file
应该是什么原因一个动态的文件名?请帮忙。由于
这需要基本调试。你看过'$ filename'吗?我想你会发现它不包含有效的文件名。 – 2011-04-30 08:58:20