2014-12-19 88 views
1

我对angular js非常陌生。动态ng模型值不适用于双向数据绑定

我使用动态字段。还有我需要创建动态NG-模型值类似领域lable.LabelID]这里lable.LabelID是动态值

,这是我的模板页面创建的形式

<form ng-submit="" ng-controller="saveOrder"> 
    <table class="col-xs-12 col-sm-8 col-sm-offset-4"> 
    <tr ng-repeat="lable in Grp.Label"> 
     <td style="width:30%" class="no-wrap text-left col-xs-text-center text-primary"> 
     <h4>{{lable.LabelName}}</h4> 
     </td> 
     <td style="width:60%" class="no-wrap text-left"> 
      <input type="{{input_type[lable.InputType]}}" 
      name="{{lable.LabelID}}" ng-model="Field[lable.LabelID]" 
      ng-init="Field[lable.LabelID] = Field[lable.LabelID] || {}"/> 
     </td> 
    </tr> 
</table> 

和我的控制器就像是

productApp.controller('saveOrder',function($scope,$http) 
{ 
    $scope.FieldOptions = {}; 
    $scope.createOrder = function() 
    { 
     alert("in"); 
     console.log($scope); 
     console.log($scope.Field[1]); 
     console.log($scope.FieldOptions); 
    } 

}); 

我服务器数据会像

{ 
    "GroupName": "Order Form", 
    "Label": [ 
    { 
     "InputType": "1", 
     "LabelID": "1", 
     "LabelName": "BillingDetails" 
    }, 
    { 
     "InputType": "1", 
     "LabelID": "2", 
     "LabelName": "shipping Details" 
    } 
    ] 
} 

对于场景我得到错误,如

TypeError: Cannot set property '1' of undefined 

at Function.v.assign (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:73:162) 
at http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:72:33 
at Object.e.$eval (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:88:347) 
at pre (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:145:309) 
at i (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:43:396) 
at e (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:39:307) 
at e (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:39:324) 
at e (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:39:324) 
at http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:38:372 
at Object.<anonymous> (http://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js:148:122) <input type="{{input_type[lable.InputType]}}" name="{{lable.LabelID}}" ng-model="Field[lable.LabelID]" ng-init="Field[lable.LabelID] = Field[lable.LabelID] || {}" class="ng-pristine ng-valid"> 

这些类型的问题,我发现很多这样。但我无法为我的方案找出解决方案。请帮我解决这个问题...

任何类型的帮助是可观的。

+0

你在哪里设置你的Grp.Label? – mfrachet 2014-12-19 06:47:53

+0

我收到来自服务器调用所有这些数据,如以这种形式{ “组名”:“订单式”, “标签”: { “的inputType”:“1”, “LabelID”:“1” , “标签”: “BillingDetails” }, { “的inputType”: “1”, “LabelID”: “2”, “标签”: “送货细节” } ] } – venkatesh 2014-12-19 06:51:27

+1

你有没有尝试在控制器中设置'$ scope.Field = [];'并删除ng-init指令? – 2014-12-19 07:04:52

回答

1

尝试在控制器内设置$scope.Field = [];并删除ng-init指令。在您当前的代码中,编译发生时$scope.Field正在变得未定义。

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