我是Selenium和XPath的新手。你能帮帮我,我正确识别的XPath的结构如下:Selenium测试的XPath标识
<body>
<div id="body-wrapper">
<div id="outer-wrapper">
<div id="wrap2">
<div class="span-24">
<div style="clear: both;"/>
<div id="header-wrapper">
<div style="clear: both;"/>
<div class="span-24">
<div class="menu-secondary-container">
<ul class="menus menu-secondary">
<li>
<li>
<li class="">
<a class="sf-with-ul" href="#">
Automation
<span class="sf-sub-indicator">»</span>
<span class="sf-sub-indicator">»</span>
</a>
<ul class="children sub-menu" style="display: none; visibility: hidden;">
<li>
<a href="http://www.ufthelp.com/p/uft.html" title="UFT">UFT</a>
</li>
我已经确定的XPath为:
("//div[@class='menutext']/descendant::ul[@class='children sub-menu']/a[@href='http://www.ufthelp.com/p/uft.html']"));
但我运行到NoSuchElementException
。请帮助我一样。谢谢
我觉得这将帮助您轻松找到他们和学习http://stackoverflow.com/questions/3030487/is-there-a-你得到的HTML是不正确的 – Garfield
尝试这个'/ * * [@ id =“header-wrapper”]/div/div/div/UL /锂[3]/UL/LI/A' – sandyJoshi