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我是新来的easyadmin包,我期待它是否可以直接从父对象 增加孩子的,所以我就3个对象: - 配方symfony的easyadmin一对多的形式
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe
*
* @ORM\Table(name="recipe")
* @ORM\Entity(repositoryClass="AppBundle\Repository\RecipeRepository")
*/
class Recipe
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=100, nullable=true)
*/
private $name;
/**
* @var \DateTime
*
* @ORM\Column(name="createdon", type="datetime", nullable=true)
*/
private $createdon;
/**
* @var string
*
* @ORM\Column(name="description", type="text", nullable=true)
*/
private $description;
/**
* @var string
*
* @ORM\Column(name="version", type="string", length=5, nullable=true)
*/
private $version;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="recipe")
*/
private $recipeproducts;
...
- Recipe_Product(其具有作为属性输入量和单位)
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe_Product
*
* @ORM\Table(name="recipe__product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\Recipe_ProductRepository")
*/
class Recipe_Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="quantity", type="decimal", precision=10, scale=2, nullable=true)
*/
private $quantity;
/**
* @ORM\ManyToOne(targetEntity="Recipe", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="recipeid", referencedColumnName="id")
* })
*/
private $recipe;
/**
* @ORM\ManyToOne(targetEntity="Product", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Productid", referencedColumnName="id")
* })
*/
private $product;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Unitid", referencedColumnName="id")
* })
*/
private $unit;
...
,当然是一个 - 产品。
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Product
*
* @ORM\Table(name="product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\ProductRepository")
*/
class Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=255)
*/
private $name;
/**
* @var string
*
* @ORM\Column(name="ref", type="string", length=25)
*/
private $ref;
/**
* @var string
*
* @ORM\Column(name="ref4stat", type="string", length=25)
*/
private $ref4Stat;
/**
* @var int
*
* @ORM\Column(name="size", type="integer")
*/
private $size;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="unitid", referencedColumnName="id")
* })
*/
private $unit;
/**
* @ORM\ManyToOne(targetEntity="ProductType", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="producttypeid", referencedColumnName="id")
* })
*/
private $producttype;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="product")
*/
private $recipeproducts;
...
当编辑配方,我想能够直接添加新recipe_product线,但我避风港t上找不到一种方式来做到这一点...
任何人有一个想法?
添加于14/10: 我找到了一种方法来呈现形式...... 我easyadmin配置文件,我创建了以下条目:
Recipe:
class: AppBundle\Entity\Recipe
form:
fields:
- name
- beer
- version
- description
- createdon
- { property: 'recipeproducts', label: 'Ingredients', type: 'collection', type_options: {entry_type: 'AppBundle\Form\Recipe_ProductType', by_reference: false} }
与表单代码为
<?php
namespace AppBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Form\Extension\Core\Type\HiddenType;
class Recipe_ProductType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('product')
->add('quantity')
->add('unit')
;
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'AppBundle\Entity\Recipe_Product'
));
}
}
这使得形式(即不要吨创建2个实体之间的链接,但必须是在管理控制器我想)