这个想法是将所有“位置”合并在一起,为我的图表提供一个数字供我阅读。所以可以说你有5个“位置”,纽约有不同的“日期”。我想将所有5个合并在一起,并输出5个数字,以及.json中合并的“Punches”。现在我有它抓住地点,并合并类似拳。但我想获得纽约实例的总数,并输出该数字。组合位置并输出来自JSON的组合数据
chart.json
[
{
"Date":"2003",
"Punches":"0",
"Locations":"New York"
},
{
"Date":"2003",
"Punches":"1",
"Locations":"New York"
},
{
"Date":"2004",
"Punches":"0",
"Locations":"Chicago"
},
{
"Date":"2004",
"Punches":"1",
"Locations":"Chicago"
},
{
"Date":"2004",
"Punches":"1",
"Locations":"Ohio"
},
{
"Date":"2004",
"Punches":"1",
"Locations":"Ohio"
},
{
"Date":"2007",
"Punches":"0",
"Locations":"Ohio"
},
{
"Date":"2007",
"Punches":"0",
"Locations":"Florida"
},
{
"Date":"2009",
"Punches":"1",
"Locations":"Florida"
},
{
"Date":"2007",
"Punches":"0",
"Locations":"New York"
},
{
"Date":"2009",
"Punches":"0",
"Locations":"New York"
},
{
"Date":"2009",
"Punches":"0",
"Locations":"Chicago"
},
{
"Date":"2010",
"Punches":"0",
"Locations":"New York"
},
{
"Date":"2010",
"Punches":"0",
"Locations":"Florida"
}
]
JS
function LocationMerge()
{
$.ajax(
{
url: 'data.json',
data:{},
dataType: 'json',
success: function(data)
{
var string = JSON.stringify(data);
var objects = $.parseJSON(string);
var categories = new Array();
var mergedPieces = new Array();
var i = 0;
_.each(objects, function(obj)
{
var existingObj;
if ($.inArray(obj.Locations, categories) >= 0)
{
existingObj = _.find(objects, function(o)
{
return o.Locations=== obj.Locations;
});
existingObj["Punches"] += obj["Punches"];
}
else
{
mergedPieces[i] = obj;
categories[i] = obj.Locations;
i++;
}
});
mergedPieces = _.sortBy(mergedPieces, function(obj)
{
return obj["Punches"];
}).reverse();
_.each(mergedPieces, function(obj)
{
var output = '';
_.each(obj, function(val, key)
{
output += key + ': ' + val + '<br>';
});
output += '<br>';
console.log(output);
});
}
});
}
谢谢!这是太棒了。 – askmeaquestion1234
@ askmeaquestion1234:请关闭解决方案,如果它适合你 –