JSON到MYSQL - JSON响应格式正确 - 循环正确？

Question

行 - 我试图为以将其插入到一个名为MySQL表“食谱”如下加载JSON响应（从外部文件名为recipes.json其中包括数以百计的食谱），它的格式为：

{ "recipeName": "After Glow Smoothie", "ingredients": "4 oz. (1/2 cup) pomegranate juice", "ingredients2": "4 oz. (1/2 cup orange juice)", "ingredients3": "2 scoops Vi-Shape shake mix", "ingredients4": "1 cup frozen pineapple", "ingredients5": "5 ice cubes"}, 
{ "recipeName": "All Berry Delight",  "ingredients": "8 oz. skim milk", "ingredients2": "2 scoops Vi-Shape shake mix", "ingredients3": "1/4 cup frozen raspberries", "ingredients4": "1/4 cup frozen blackberries", "ingredients5": "1/4 cup frozen strawberries", "ingredients6": "1/4 cup frozen dark cherries", "ingredients7": "5 ice cubes"} 

我不太习惯数组，所以我想知道为什么我不能通过食谱循环并正确插入它们。我的JSON格式不正确，还是我这样的PHP noob，我在我的主代码中犯了错误。供参考如下：

<?php 
header('Content-Type: text/html; charset=utf-8'); 

$hostname_ndb = "localhost"; 
$database_ndb = "test"; 
$username_ndb = "root"; 
$password_ndb = "root"; 
$ndb = mysql_pconnect($hostname_ndb, $username_ndb, $password_ndb) or trigger_error(mysql_error(),E_USER_ERROR); 

$url = "http://localhost:8888/shakerecipes/recipes.json"; 


$json = file_get_contents($url); 
// var_dump(json_decode($json, true)); 
$out = json_decode($json, true); 


foreach($out["recipeName"] as $recipeNames) { 
$name = addslashes($recipeNames[recipeName]); 
$ingredients= addslashes($recipeNames[ingredients]); 
$ingredients2 = addslashes($recipeNames[ingredients2]); 
$ingredients3 = addslashes($recipeNames[ingredients3]); 
$ingredients4 = addslashes($recipeNames[ingredients4]); 
$ingredients5 = addslashes($recipeNames[ingredients5]); 
$ingredients6 = addslashes($recipeNames[ingredients6]); 
$ingredients7 = addslashes($recipeNames[ingredients7]); 
$ingredients8 = addslashes($recipeNames[ingredients8]); 
$ingredients9 = addslashes($recipeNames[ingredients9]); 

mysql_query("INSERT INTO test (recipeName, ingredients, ingredients2, ingredients3, ingredients4, ingredients5, ingredients6, ingredients7, ingredients8, ingredients9) VALUES('$name', '$ingredients', '$ingredients2', '$ingredients3', '$ingredients4', '$ingredients5', '$ingredients6', '$ingredients7', '$ingredients8', '$ingredients9')") or die (mysql_error()); 
} 
?> 

感谢您的任何和所有提示/帮助。

BRR

Answer 1

对于那些谁不知道什么工作 - 这里是我想出了：

<?php 
header('Content-Type: text/html; charset=utf-8'); 

$hostname_ndb = "localhost"; 
$database_ndb = "test"; 
$username_ndb = "root"; 
$password_ndb = "root"; 
$ndb = mysql_pconnect($hostname_ndb, $username_ndb, $password_ndb) or trigger_error(mysql_error(),E_USER_ERROR); 
mysql_select_db($database_ndb); 

$url = "http://localhost:8888/shakerecipes/recipes.json"; 
$json = file_get_contents($url); 

$out = json_decode($json, true); 

foreach($out["recipes"] as $recipe) { 
$name = addslashes($recipe[recipeName]); 
$ingredients= addslashes($recipe[ingredients]); 
$ingredients2 = addslashes($recipe[ingredients2]); 
$ingredients3 = addslashes($recipe[ingredients3]); 
$ingredients4 = addslashes($recipe[ingredients4]); 
$ingredients5 = addslashes($recipe[ingredients5]); 
$ingredients6 = addslashes($recipe[ingredients6]); 
$ingredients7 = addslashes($recipe[ingredients7]); 
$ingredients8 = addslashes($recipe[ingredients8]); 
$ingredients9 = addslashes($recipe[ingredients9]); 

mysql_query("INSERT INTO recipes (recipeName, ingredients, ingredients2, ingredients3, ingredients4, ingredients5, ingredients6, ingredients7, ingredients8, ingredients9) VALUES('$name', '$ingredients', '$ingredients2', '$ingredients3', '$ingredients4', '$ingredients5', '$ingredients6', '$ingredients7', '$ingredients8', '$ingredients9')") or die (mysql_error()); 

} 
?> 

Answer 2

首先，你应该使用mysql_real_escape_string，而不是和addslashes的。

其次你应该/可以预制另一个foreach循环与$ recipeNames。

或者你可以做到lambda /封闭风格。

array_walk($recipeNames, function(&$value) { 
    $value = mysql_real_escape_string($value); 
}); 

之后，你可以爆你的价值观

mysql_query("INSERT INTO test (recipeName, ingredients, ingredients2, ingredients3, ingredients4, ingredients5, ingredients6, ingredients7, ingredients8, ingredients9) VALUES('".implode('\',\'', $recipeNames)."')") or die (mysql_error());