2017-05-26 89 views
1

我有以下SQL其拉动从嵌套表根节点(相对于用户,即该用户被分配了此最高节点),锋whereNotExists不产生正确

SELECT 
    child_domain.*, child_subscription.user_id 
FROM 
    domains AS child_domain 
JOIN subscriptions 
    AS child_subscription 
    ON child_subscription.domain_id = child_domain.id 
WHERE NOT EXISTS 
    (
     SELECT 1 
     FROM domains AS parent_domain 
     JOIN subscriptions 
      AS parent_subscription 
      ON parent_subscription.domain_id = parent_domain.id 
     WHERE 
      parent_domain.start < child_domain.start 
     AND 
      parent_domain.end > child_domain.end 
     AND 
      parent_subscription.user_id = child_subscription.user_id 
    ); 

上述返回嵌套行的根节点,该表是这个样子,

----------- ----------------- --------- 
| DOMAINS | | SUBSCRIPTIONS | | USERS | 
----------- ----------------- --------- 
| id  | | user_id  | | id | 
| start | | domains_id | | name | 
| end  | ----------------- --------- 
----------- 

但是,我无法将其转换为侃侃而谈。问题似乎在子查询中(我试过whereDoesntHavewhereNotExists,但都没有工作)。

DB::table('domains as child_domain') 
    ->join('subscriptions as child_subscription','child_subscription.domain_id','child_domain.id') 
    ->whereNotExists('domains as parent_domain',function($query){ 
     $query 
     ->join('subscriptions as parent_subscription','parent_subscription.domain_id','parent_domain.id') 
     ->where('parent_domain.end','>','parent_domain.end') 
     ->where('parent_domain.start'.'<','parent_domain.start') 
     ->where('parent_subscription.user_id', 'child_subscription.user_id')->get(); 
}); 

上面的代码中,当我输出toSql()所示,

select * from `domains` as `child_domain` inner join `subscriptions` as `child_subscription` on `child_subscription`.`domain_id` = `child_domain`.`id` where not exists (select *) 

理解任何帮助。

回答

0

测试并生成你想要的。

DB::table('domains as child_domain') 
    ->join('subscriptions as child_subscription', 'child_subscription.domain_id', 'child_domain.id') 
    ->whereNotExists(function($query) { 
     $query->selectRaw(1) 
      ->from('domains as parent_domain') 
      ->join('subscriptions as parent_subscription', 'parent_subscription.domain_id', 'parent_domain.id') 
      ->whereColumn('parent_domain.start', '<', 'child_domain.start') 
      ->whereColumn('parent_domain.end', '>', 'child_domain.end') 
      ->whereColumn('parent_subscription.user_id', 'child_subscription.user_id'); 
    }) 
    ->select('child_domain.*', 'child_subscription.user_id') 
    ->get(); 

查询制作

select `child_domain`.*, `child_subscription`.`user_id` from `domains` as `child_domain` inner join `subscriptions` as `child_subscription` on `child_subscription`.`domain_id` = `child_domain`.`id` where not exists (select 1 from `domains` as `parent_domain` inner join `subscriptions` as `parent_subscription` on `parent_subscription`.`domain_id` = `parent_domain`.`id` where `parent_domain`.`start` < `child_domain`.`start` and `parent_domain`.`end` > `child_domain`.`end` and `parent_subscription`.`user_id` = `child_subscription`.`user_id`) 
+0

谢谢!这很完美(虽然在whereColumn中有一个小错误,他们比较自己而不是他们的孩子)。 – DGeo

+0

@DGeo更新。我在问题中根据您的查询回答了问题。没有注意到它。 – Sandeesh

+0

啊,我刚刚发现,现在,我的坏。再次感谢。 – DGeo