我看到3个简单的解决方案:
1)最慢的方法是使用CALL,这样你就不需要你的循环中延迟扩展。
@echo off & setlocal disableDelayedExpansion
set "dest=%~dpn1"
IF "%1" equ "" Set "dest=%cd%"
set /a Folders=0
set /a FoldersWithSubFoldersAndFiles=0
set /a FoldersWithOnlyFiles=0
set /a FoldersWithOnlySubFolders=0
set /a FoldersEmpty=0
for /f "usebackq tokens=*" %%a in (`DIR /AD /S /B "%dest%"`) do (
Set /a Folders+=1
for /f "usebackq tokens=*" %%i in (`DIR "%%a" /A-D /B 2^>NUL^| FIND /C /V ""`) do (
Set NumberOfFiles=%%i
)
for /f "usebackq tokens=*" %%i in (`DIR "%%a" /AD /B 2^>NUL^| FIND /C /V ""`) do (
set NumberOfFolders=%%i
)
call :incrementCounts
)
echo Found %Folders% folders below "%dest%".
echo %FoldersWithSubFoldersAndFiles% folders containing files and subfolders.
echo %FoldersWithOnlyFiles% folders containing files only.
echo %FoldersWithOnlySubFolders% folders containing subfolders only.
echo %FoldersEmpty% folders are empty.
echo See dircount.log for list of empty folders.
endlocal
exit /b
:incrementCounts
IF "%NumberOfFiles%" neq "0" IF "%NumberOfFolders%" neq "0" set /a FoldersWithSubFoldersAndFiles+=1
IF "%NumberOfFiles%" neq "0" IF "%NumberOfFolders%" equ "0" set /a FoldersWithOnlyFiles+=1
IF "%NumberOfFiles%" equ "0" IF "%NumberOfFolders%" neq "0" set /a FoldersWithOnlySubFolders+=1
IF "%NumberOfFiles%" equ "0" IF "%NumberOfFolders%" equ "0" (
set /a FoldersEmpty+=1
echo %%a is empty.
)
exit /b
2)更快的方法是临时启用延迟扩展,只需将该值传递给FOR变量即可。
@echo off & setlocal disableDelayedExpansion
set "dest=%~dpn1"
IF "%1" equ "" Set "dest=%cd%"
set /a Folders=0
set /a FoldersWithSubFoldersAndFiles=0
set /a FoldersWithOnlyFiles=0
set /a FoldersWithOnlySubFolders=0
set /a FoldersEmpty=0
for /f "usebackq tokens=*" %%a in (`DIR /AD /S /B "%dest%"`) do (
Set /a Folders+=1
for /f "usebackq tokens=*" %%i in (`DIR "%%a" /A-D /B 2^>NUL^| FIND /C /V ""`) do (
Set NumberOfFiles=%%i
)
for /f "usebackq tokens=*" %%i in (`DIR "%%a" /AD /B 2^>NUL^| FIND /C /V ""`) do (
set NumberOfFolders=%%i
)
setlocal enableDelayedExpansion
for /f "tokens=1,2" %%N in ("!NumberOfFiles! !NumberOfFolders!") do (
endlocal
IF "%%N" neq "0" IF "%%M" neq "0" set /a FoldersWithSubFoldersAndFiles+=1
IF "%%N" neq "0" IF "%%M" equ "0" set /a FoldersWithOnlyFiles+=1
IF "%%N" equ "0" IF "%%M" neq "0" set /a FoldersWithOnlySubFolders+=1
IF "%%N" equ "0" IF "%%M" equ "0" (
set /a FoldersEmpty+=1
echo %%a is empty.
)
)
)
echo Found %Folders% folders below "%dest%".
echo %FoldersWithSubFoldersAndFiles% folders containing files and subfolders.
echo %FoldersWithOnlyFiles% folders containing files only.
echo %FoldersWithOnlySubFolders% folders containing subfolders only.
echo %FoldersEmpty% folders are empty.
echo See dircount.log for list of empty folders.
endlocal
3)但我会处理它的方式是消除只在循环内使用的2个变量。它们不在循环外部使用,并且它们已经从FOR变量派生。由于所有东西现在都是FOR变量,所以不再需要延迟扩展。
@echo off & setlocal ENABLEEXTENSIONS ENABLEDELAYEDEXPANSION
set "dest=%~dpn1"
IF "%1" equ "" Set "dest=%cd%"
set /a Folders=0
set /a FoldersWithSubFoldersAndFiles=0
set /a FoldersWithOnlyFiles=0
set /a FoldersWithOnlySubFolders=0
set /a FoldersEmpty=0
for /f "usebackq tokens=*" %%a in (`DIR /AD /S /B "%dest%"`) do (
Set /a Folders+=1
for /f "usebackq tokens=*" %%N in (`DIR "%%a" /A-D /B 2^>NUL^| FIND /C /V ""`) do (
for /f "usebackq tokens=*" %%M in (`DIR "%%a" /AD /B 2^>NUL^| FIND /C /V ""`) do (
IF "%%N" neq "0" IF "%%M" neq "0" set /a FoldersWithSubFoldersAndFiles+=1
IF "%%N" neq "0" IF "%%M" equ "0" set /a FoldersWithOnlyFiles+=1
IF "%%N" equ "0" IF "%%M" neq "0" set /a FoldersWithOnlySubFolders+=1
IF "%%N" equ "0" IF "%%M" equ "0" (
set /a FoldersEmpty+=1
echo %%a is empty.
)
)
)
)
echo Found %Folders% folders below "%dest%".
echo %FoldersWithSubFoldersAndFiles% folders containing files and subfolders.
echo %FoldersWithOnlyFiles% folders containing files only.
echo %FoldersWithOnlySubFolders% folders containing subfolders only.
echo %FoldersEmpty% folders are empty.
echo See dircount.log for list of empty folders.
endlocal
哎!非常感谢!我想我喜欢所有三种变体 - 并且再次了解到有关cmd特殊处理的知识:-)。但DelayedExpansion完全禁用:那么文件夹名称中的&符号是否不会破坏脚本?不过:我会试试看,明天再报告。已经从这里开始了晚上... Martin – CmdQuestion 2013-03-05 23:22:11
@CmdQuestion - 文件或文件夹名称中的&符号不应该对任何选项造成任何问题。 – dbenham 2013-03-06 05:15:54
作品!现在好的程序:-)马丁 – CmdQuestion 2013-03-07 16:10:29