ORDER BY上PLSQL

Question

问题

我已经设置的数据应取出来，应该按以下顺序

Last Name  First Name  Location 
Blake   James   101007 
fusio   Wiko   101008 
        100 Total 

FAROMOJU  BANKOLE   303315 
Gibbs   Rhonda   303315 
Greene   Leette   303315 
        331 Total 

...... 
............ 

在该准备一份报告，我们可以看到，3字母代码 [从提取位置代码 - CONCAT（SUBSTR（COLUMN3,3,3），'Total'）]在所有位置设置后。我只是想出报告，除了地点代码降序的情况外，它工作得很好。它使用'位置'进行排序后，将其转换为3个字母的代码，而不是使用完整的数字代码。所以在结果中降序不能很好地工作，因为我需要。请给我一个解决方案，

我附上我的代码，

****************************************************** 

FUNCTION GET_ACTY_SUMMARY(V_STARTDATE IN DATE,V_ENDDATE IN DATE) 
RETURN TEMP_OUTPUT_TABLE PIPELINED IS 
CURSOR ACTY_SUMMARY IS 

/* The query fetches the report field grouped by First Name,Last Name 
and Location.*/ 

    SELECT 
      COLUMN1 AS LASTNAME, 
      COLUMN2 AS FIRSTNAME, 
      COLUMN3 AS LOCATION, 
      SUM(COLUMN4) AS ACTIVITYNM1, 
      SUM(COLUMN5) AS ACTIVITYNM2, 
      SUM(COLUMN6) AS ACTIVITYNM3, 
      SUM(COLUMN7) AS ACTIVITYNM4, 
      SUM(COLUMN8) AS ACTIVITYNM5, 
      SUM(COLUMN9) AS REG_HRS, 
      SUM(COLUMN10) AS OT_HRS, 
      SUM(COLUMN11) AS TOTAL_HRS, 
      SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 

    FROM 
    TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
    GROUP BY 
    COLUMN1, 
    COLUMN2, 
    COLUMN3 


    UNION 

    SELECT NULL, 
     NULL, 
     CONCAT(SUBSTR(COLUMN3,3,3),'Total'), 
     SUM(COLUMN4) AS ACTIVITYNM1, 
     SUM(COLUMN5) AS ACTIVITYNM2, 
     SUM(COLUMN6) AS ACTIVITYNM3, 
     SUM(COLUMN7) AS ACTIVITYNM4, 
     SUM(COLUMN8) AS ACTIVITYNM5, 
     SUM(COLUMN9) AS REG_HRS, 
     SUM(COLUMN10) AS OT_HRS, 
     SUM(COLUMN11) AS TOTAL_HRS, 
     SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 

    FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
    GROUP BY COLUMN3 
    UNION 

    SELECT NULL, 
     NULL, 
     'Total', 
     SUM(COLUMN4) AS ACTIVITYNM1, 
     SUM(COLUMN5) AS ACTIVITYNM2, 
     SUM(COLUMN6) AS ACTIVITYNM3, 
     SUM(COLUMN7) AS ACTIVITYNM4, 
     SUM(COLUMN8) AS ACTIVITYNM5, 
     SUM(COLUMN9) AS REG_HRS, 
     SUM(COLUMN10) AS OT_HRS, 
     SUM(COLUMN11) AS TOTAL_HRS, 
     SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 

    FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 


    ORDER BY 3 desc ; 

GAS ACTY_SUMMARY%ROWTYPE; 

/*Intialize the table output format with NULL.*/ 

TT TEMP_OUTPUT_FORMAT := INITIALIZE_TABLE_FORMAT(); 
    BEGIN 
    OPEN ACTY_SUMMARY; 
    FETCH ACTY_SUMMARY INTO GAS; 
    WHILE ACTY_SUMMARY%FOUND LOOP 
     BEGIN 
     TT.COLUMN1 := GAS.LASTNAME; 
     TT.COLUMN2 := GAS.FIRSTNAME; 
     TT.COLUMN3 := GAS.LOCATION; 
     TT.COLUMN4 := GAS.ACTIVITYNM1; 
     TT.COLUMN5 := GAS.ACTIVITYNM2; 
     TT.COLUMN6 := GAS.ACTIVITYNM3; 
     TT.COLUMN7 := GAS.ACTIVITYNM4; 
     TT.COLUMN8 := GAS.ACTIVITYNM5; 
     TT.COLUMN9 := GAS.REG_HRS; 
     TT.COLUMN10 := GAS.OT_HRS; 
     TT.COLUMN11 := GAS.TOTAL_HRS; 
     TT.COLUMN12 := GAS.PRODUCTIVITY_PERCENTAGE; 
     PIPE ROW(TT); 
    END; 
    FETCH ACTY_SUMMARY INTO GAS; 
    END LOOP; 
    CLOSE ACTY_SUMMARY; 
    RETURN; 
END GET_ACTY_SUMMARY; 

END GEHC_ACTY_REPT_PKG; 


****************************************************** 

感谢 阿南德

Answer 1

我建议你更改查询是

SELECT 
      COLUMN1 AS LASTNAME, 
      COLUMN2 AS FIRSTNAME, 
      COLUMN3 AS LOCATION, 
      COLUMN3 AS FULL_LOCATION, 
      SUM(COLUMN4) AS ACTIVITYNM1, 
      SUM(COLUMN5) AS ACTIVITYNM2, 
      SUM(COLUMN6) AS ACTIVITYNM3, 
      SUM(COLUMN7) AS ACTIVITYNM4, 
      SUM(COLUMN8) AS ACTIVITYNM5, 
      SUM(COLUMN9) AS REG_HRS, 
      SUM(COLUMN10) AS OT_HRS, 
      SUM(COLUMN11) AS TOTAL_HRS, 
      SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
    FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
    GROUP BY 
    COLUMN1, 
    COLUMN2, 
    COLUMN3 
UNION ALL 
    SELECT NULL, 
     NULL, 
     CONCAT(SUBSTR(COLUMN3,3,3),'Total'), 
     COLUMN3 AS FULL_LOCATION, 
     SUM(COLUMN4) AS ACTIVITYNM1, 
     SUM(COLUMN5) AS ACTIVITYNM2, 
     SUM(COLUMN6) AS ACTIVITYNM3, 
     SUM(COLUMN7) AS ACTIVITYNM4, 
     SUM(COLUMN8) AS ACTIVITYNM5, 
     SUM(COLUMN9) AS REG_HRS, 
     SUM(COLUMN10) AS OT_HRS, 
     SUM(COLUMN11) AS TOTAL_HRS, 
     SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
    FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
    GROUP BY COLUMN3 
UNION ALL 
    SELECT NULL, 
     NULL, 
     'Total', 
     'Total' AS FULL_LOCATION, 
     SUM(COLUMN4) AS ACTIVITYNM1, 
     SUM(COLUMN5) AS ACTIVITYNM2, 
     SUM(COLUMN6) AS ACTIVITYNM3, 
     SUM(COLUMN7) AS ACTIVITYNM4, 
     SUM(COLUMN8) AS ACTIVITYNM5, 
     SUM(COLUMN9) AS REG_HRS, 
     SUM(COLUMN10) AS OT_HRS, 
     SUM(COLUMN11) AS TOTAL_HRS, 
     SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
    FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
    ORDER BY 4 DESC; 

我们正在试图这里要做的是在查询中添加完整的位置（数据中的COLUMN3，如果我正在读取原始查询），以便排序可以基于它。您可能需要更改GROUP BY的 - 我不确定，也没有可供您测试的数据。但这是基本的想法。

分享和享受。

Answer 2

我会建议看看分组集，而不是使用联合数据在一起。分组集（与CUBE和ROLLUP一起）是汇总多个级别的数据的方法，这是您似乎在做的事情。使用分组集合将获得您正在查找的数据。

为了排序数据，您需要向order by子句添加其他列。我使用的grouping_id（）函数返回一个数字（0或1），这取决于它是否是给定表达式的'superaggregate'行。这些'superaggregate'行是与总计和小计相关的附加行。我正在对数据进行排序以及该列是否是超级聚集的。

认为你应该能够做到像：

SELECT 
    COLUMN1 AS LASTNAME, 
    COLUMN2 AS FIRSTNAME, 
    case 
    when grouping_id(column3, substr(column3,3,3)) = 3 then 'Total' 
    when grouping_id(column3, substr(column3,3,3)) = 2 
     then substr(column3,3,3) ||' Total' 
    else column3 end as location, 
    SUM(COLUMN4) AS ACTIVITYNM1, 
    SUM(COLUMN5) AS ACTIVITYNM2, 
    SUM(COLUMN6) AS ACTIVITYNM3, 
    SUM(COLUMN7) AS ACTIVITYNM4, 
    SUM(COLUMN8) AS ACTIVITYNM5, 
    SUM(COLUMN9) AS REG_HRS, 
    SUM(COLUMN10) AS OT_HRS, 
    SUM(COLUMN11) AS TOTAL_HRS, 
    SUM(COLUMN12) AS PRODUCTIVITY_PERCENTAGE 
FROM TABLE(ACTY_COLUMN(V_STARTDATE,V_ENDDATE)) 
GROUP BY grouping sets ((), (substr(column3,3,3)), 
    (COLUMN1,COLUMN2,COLUMN3, substr(column3,3,3))) 
order by 
    grouping_id(substr(column3,3,3)), 
    substr(column3,3,3) desc, 
    grouping_id(column3, substr(column3,3,3)), 
    column3 desc 

有望运行更快，做你想做的。我可能已经使order by子句比必要的更复杂，但它应该做你需要的。