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我正在研究一个puppet清单,以从CVS存储库部署我们的代码。我见到目前为止如下:工作副本的CVS返回状态修订版
define codedeploy::cvs ($module, $tag, $copydir) {
file { "$copydir":
owner => www-data,
group => www-data,
mode => 755,
ensure => directory
}
#bypass cvs login, we'll just inject a ~/.cvspass file
# to do
#initial cvs checkout
exec { "cvscheckout-$name":
command => "cvs co -r $tag -d $name $module",
creates => "$copydir/$name/CVS",
require => [Package[cvs], File["$copydir"]],
environment => "CVSROOT=:pserver:[email protected]:/cvs/repository",
cwd => "$copydir"
}
#cvs update to tag
exec { "cvsupdate-$name":
command => "cvs up -r $tag",
require => [Package[cvs], File["$copydir"], Exec["cvscheckout-$name"] ],
environment => "CVSROOT=:pserver:[email protected]:/cvs/repository",
cwd => "$copydir/$name",
unless => #NEED TO FIGURE THIS PART OUT!
}
}
,我不知道是我怎么能返回工作拷贝的修订状态,这样才不会打电话CVS更新每个木偶运行的一部分。 cvs是否有一个命令来返回整个工作树的当前标签或版本ID?当我做一个cvs差异时,它似乎知道它应该区分该标签下的所有文件,但是我不确定在检出后如何才能返回工作副本的标签ID。
谢谢!