为什么我在squigly括号旁出现错误？

Question

当我运行这段代码时，我应该不会收到任何错误，但是我和它的右边是那些波浪形的括号。我已经改变了的东西和移动的东西，改变了代码，但这个错误是永远存在的：

var name = prompt("What is your name?"); 
var bosshp = 150; 
var playhp = 100; 
alert("You are going to fight a boss"); 
alert("You have 100hp while the boss has 150hp, you deal between 1 and 10 damage while he does between 1 and 15 damage."); 
alert("You have two actions and two special abilities. Your moves are block, and attack. Blocking heals you for 5 while attacking attacks...Your special abilities are crit chance and dodge chance. There is a 25% chance to deal double damage and a 15% chance that you will dodge the bosses attack!"); 
alert("Ok " + name + ", You have to fight Gorlock, the monkey king. "); 
do 
{ 
    var q = prompt("What will be your first move?\nEnter either 'block' or 'attack'"); 
    if (q === "block") 
    { 
     playhp = playhp + 5; 
    } 
    else if (q === "attack") 
    { 
     function attack(); 
    } 
} 
while (bosshp >= 0 || playhp >= 0); 


function attack() { 
    if ((Math.floor((Math.random() * 100) + 1)) < 16) { 
     bosshp = bosshp - (Math.floor((Math.random() * 10) + 1) * 2); 
    } else { 
     bosshp = bosshp - (Math.floor((Math.random() * 10) + 1)); 
    } 
} 

Answer 1

，因为你定义当你真正称之为

else if (q === "attack") 
{ 
    function attack(); 
    ^^^^^^^^ 
} 

删除功能的功能

else if (q === "attack") 
{ 
    attack(); 
} 

使用像http://www.jshint.com/或http://www.jslint.com/