如何比较Python中的字符串中的2行

Question

我在Python中将控制台输出存储在字符串中。

它看起来像：

output ="Status of xyz 
     Process is running 

     Status of abc 
     Process is stopped" 

我想每行的最后一个字，并与下一行的最后一个字比较。 我如何在Python中做到这一点？

Answer 1

首先，你需要将字符串分成行的列表：

lines = output.split('\n') #splits into lines 

然后，你需要遍历所有的线和分割线成词

#we go through all lines except the last, to check the line with the next 
for lineIndex in range(len(lines)-1): 
    # split line to words 
    WordsLine1 = lines[lineIndex].split() 
    WordsLine2 = lines[lineIndex+1].split() # split next line to words 
    #now check if the last word of the line is equal to the last word of the other line. 
    if (WordsLine1[-1] == WordLine2[-1]): 
     #equal do stuff.. 

Answer 2

这里的数据

data = """\ 
Status of xyz Process is running 
Status of abc Process is stopped 
"""  

以跨平台方式拆分成行：

lines = data.splitlines() 

遍历两两行，所以你必须在同一时间的当前行和前一行（使用zip）：

for previous, current in zip(lines, lines[1:]): 
    lastword = previous.split()[-1] 
    if lastword == current.split()[-1]: 
     print('Both lines end with the same word: {word}'.format(word=lastword)) 

另外，如果你不喜欢怎么zip长相，我们可以通过重复设置一个变量来存储最后一行来成对循环遍历行：

last = None 
for line in lines: 
    if last is not None and line.split()[-1] == last.split()[-1]: 
     print('both lines have the same last word') 
    last = line