如何通过API从维基百科获得地标地点的标题？

Question

对于我的代码，我使用维基百科API，该维基百科API提供链接到与该城市的维基百科文章链接的所有地方的链接。但是用我的代码有一些额外的不必要的链接。我只想返回类型为“地标”的链接。

我的维基百科API是：

https://en.wikipedia.org/w/api.php?action=query&list=geosearch&gsradius=10000&gspage=Berlin&gslimit=500&gsprop=type|name|dim|country|region|globe&format=json 

从维基百科API示例JSON数据：

"query": { 
    "geosearch": [ 
     { 
      "pageid": 5858187, 
      "ns": 0, 
      "title": "Stuttgart Hauptbahnhof", 
      "lat": 48.783888888889, 
      "lon": 9.1816666666667, 
      "dist": 136.8, 
      "primary": "", 
      "type": "railwaystation", 
      "name": "", 
      "dim": 1000, 
      "country": "DE", 
      "region": "BW" 
     }, 
     { 
      "pageid": 6102287, 
      "ns": 0, 
      "title": "Staatstheater Stuttgart", 
      "lat": 48.780277777778, 
      "lon": 9.185, 
      "dist": 361, 
      "primary": "", 
      "type": "landmark", 
      "name": "", 
      "dim": "900", 
      "country": "DE", 
      "region": "BW" 
     }, 
     { 
      "pageid": 35806545, 
      "ns": 0, 
      "title": "Versatel building", 
      "lat": 48.78409, 
      "lon": 9.17799, 
      "dist": 400.4, 
      "primary": "", 
      "type": null, 
      "name": "", 
      "dim": 1000, 
      "country": null, 
      "region": null 
     }, 
     { 
      "pageid": 3230957, 
      "ns": 0, 
      "title": "Neue Staatsgalerie", 
      "lat": 48.780277777778, 
      "lon": 9.1869444444444, 
      "dist": 430.6, 
      "primary": "", 
      "type": "landmark", 
      "name": "", 
      "dim": 1000, 
      "country": "DE", 
      "region": "BW" 
     }, 
     .... 
    ] 
} 

我的代码从这个API得到Title。

using (var client = new HttpClient()) 
{ 
    var response = client.GetAsync("https://en.wikipedia.org/w/api.php?action=query&list=geosearch&gsradius=10000&gspage=Berlin&gslimit=500&gsprop=type|name|dim|country|region|globe&format=json").Result; 
    if (response.IsSuccessStatusCode) 
    { 
     var responseContent = response.Content; 
     string responseString = responseContent.ReadAsStringAsync().Result; 
     var obj = JsonConvert.DeserializeObject<RootObject>(responseString).query.geosearch.Select(a => a.title).ToList(); 

     foreach (var item in obj) 
     { 
      Console.WriteLine(item); 
     } 
    } 
} 

下面是电流输出：

我怎样才能得到的结果，其中type是 “里程碑式” 的称号？

Answer 1

如果使用JSON格式，试试这个：

var obj = JsonConvert.DeserializeObject<RootObject>(responseString).query.geosearch 
    .Where(a => a.type == "landmark").Select(a => a.title).ToList(); 

你也可以得到所有标题不使用Json.NET。这是我如何使用XML格式：

using (var webResponse = (HttpWebResponse)WebRequest.Create("https://en.wikipedia.org/w/api.php?action=query&list=geosearch&gsradius=10000&gspage=Berlin&gslimit=500&gsprop=type&format=xml").GetResponse()) 
{ 
    using (var reader = new StreamReader(webResponse.GetResponseStream())) 
    { 
     var response = XElement.Parse(reader.ReadToEnd()); 
     var obj = response.Descendants("gs") 
      .Where(a => a.Attribute("type") != null && a.Attribute("type").Value == "landmark") 
      .Select(a => a.Attribute("title").Value).ToList(); 
    } 
} 

Answer 2

我不知道C＃:-)

但尝试这样的事：

var geosearch = JsonConvert.DeserializeObject<RootObject>(responseString).query.geosearch; 
var landmarks = geosearch.Where(type => type == "landmark");