Java Processbuilder - 执行一个不在OS X上的路径的文件

Question

好的，我想让ChucK在导出的Processing草图中可用，也就是说，如果我从Processing中导出应用程序，ChucK VM二进制文件将从应用程序。所以作为上述应用程序的用户，您根本无需担心ChucK在您的路上。

现在我正在生成和执行bash脚本文件，但这种方式我不从查得到任何控制台输出回处理：

#!/bin/bash 
cd "[to where the Chuck executable is located]" 
./chuck --kill 
killall chuck # just to make sure 
./chuck chuckScript1.ck cuckScriptn.ck 

然后

Process p = Runtime.getRuntime().exec("chmod 777 "+scriptPath); 
p = Runtime.getRuntime().exec(scriptPath); 

这但我想直接从Processing处理ChucK，但无法执行：

String chuckPath = "[folder in which the chuck executable is located]" 
ProcessBuilder builder = new ProcessBuilder 
           (chuckPath+"/chuck", "test.ck"); 

     final Process process = builder.start(); 
     InputStream is = process.getInputStream(); 
     InputStreamReader isr = new InputStreamReader(is); 
     BufferedReader br = new BufferedReader(isr); 
     String line; 
     while((line = br.readLine()) != null) println(line); 
     println("done chuckin'! exitValue: " + process.exitValue()); 

对不起，如果这是新手风格：D

Answer 1

ProcessBuilder builder = new ProcessBuilder 
           (chuckPath+"/chuck", chuckPath+"/test.ck"); 

参数都需要一个绝对路径。