MySQL的时间戳比较问题

嗨，我曾在MySQL查询疑问MySQL的时间戳比较问题

mysql> SELECT * from share5; 
+----+-------+--------------+--------+-------+---------------------+ 
| Id | Price | State  | Symbol | Trade | created_date  | 
+----+-------+--------------+--------+-------+---------------------+ 
| 1 | 120 | maharashtra | mh  | buy | 2017-09-12 12:18:11 | 
| 1 | 121 | maharashtra | mh  | buy | 2017-09-12 12:18:36 | 
| 2 | 122 | karnataka | ka  | sell | 2017-09-12 12:19:26 | 
| 2 | 123 | karnataka | ka  | sell | 2017-09-12 12:20:00 | 
| 3 | 124 | tamil nadu | tn  | buy | 2017-09-12 12:20:30 | 
| 3 | 125 | tamil nadu | tn  | buy | 2017-09-12 12:20:43 | 
| 4 | 127 | andrapradesh | ap  | buy | 2017-09-12 12:26:26 | 
| 4 | 126 | andrapradesh | ap  | buy | 2017-09-12 12:26:39 | 
| 4 | 126 | andrapradesh | ap  | buy | 2017-09-12 16:57:19 | 
+----+-------+--------------+--------+-------+---------------------+

我想通过比较2个ID对如来选择指数最新值以上，我想通过比较时间戳来筛选出最新的一个。我尝试了下面的一个，但它只给出了第一个不是最新的附加值。是否可以比较两个ID并筛选出最新的ID？

mysql> SELECT price,id,state,symbol,trade,created_date from share5 group by id ; 
+-------+----+--------------+--------+-------+---------------------+ 
| price | id | state  | symbol | trade | created_date  | 
+-------+----+--------------+--------+-------+---------------------+ 
| 120 | 1 | maharashtra | mh  | buy | 2017-09-12 12:18:11 | 
| 122 | 2 | karnataka | ka  | sell | 2017-09-12 12:19:26 | 
| 124 | 3 | tamil nadu | tn  | buy | 2017-09-12 12:20:30 | 
| 127 | 4 | andrapradesh | ap  | buy | 2017-09-12 12:26:26 | 
+-------+----+--------------+--------+-------+---------------------+

来源

2017-09-14 program sample

尝试从share5组中通过id DESC选择价格，id，状态，符号，trade，created_date; –

从每个组获得最新的行，你可以使用下面的查询

select t.* 
from share5 t 
join (
    select Id,max(created_date) created_date 
    from share5 
    group by Id 
) t1 using(Id,created_date)

DEMO

来源

2017-09-14 07:30:42

其工作感谢代码khalid –

好像你缺少ORDER_BY，你可以尝试

SELECT price,id,state,symbol,trade,created_date from share5 group by id order by created_date desc;

来源

2017-09-14 07:30:49 rypskar

尝试这个：

SELECT price,id,state,symbol,trade,created_date from share5 where created_date = (select max(created_date)from Customers) group by id,price,state,symbol,trade,created_date

来源

2017-09-14 07:49:07 Fari

MySQL的时间戳比较问题

回答

相关问题