Paginate使用Laravel 5和Propel ORM

我正在尝试将分页6最大结果分配给每个页面。Paginate使用Laravel 5和Propel ORM

这是我在控制器代码：

public function brand_new(Request $request) 
    { 
$current_page = $request->get('page', 1); 
$find_vehicles = $this->filterAll();//retrieving all the vehicles by calling a method 
     $total = $find_vehicles->count(); 
     $paginator = new LengthAwarePaginator($find_vehicles, $total, 6, $current_page); 
     $paginator->setPath($request->getBasePath()); 
return view('pages.massSearch',compact('paginator'));

这是我在* .blade.php代码：

@foreach($paginator->getCollection()->all() as $pg) 
    {{ $pg->ImagePath }} {{--ImagePath is the php name of a table column--}} 
    @endforeach

但我发现了错误：试图获得非物件的财产

任何建议，将有助于...

filterAll方法：

public function filterAll($val) 
    { 
     $filter_avl = VehicleQuery::create() 
      ->filterByAvailability(true) 
      ->find(); 
     $filter_modelAvl = VehicleQuery::create() 
      ->useVModelQuery() 
      ->filterByAvailability(true) 
      ->endUse() 
      ->find(); 
     $filter_bndAvl = VehicleQuery::create() 
      ->useVBrandQuery() 
      ->filterByAvailability(true) 
      ->endUse() 
      ->find(); 

     $filter_cStatus = VehicleQuery::create() 
      ->useCurrrentStatusQuery() 
      ->endUse() 
      ->find(); 
     $filter_mode = VehicleQuery::create() 
      ->useVehicleModeQuery() 
      ->filterByModeName($val) 
      ->endUse() 
      ->find(); 

     $find_vehicles = VehicleImagesQuery::create() 
      ->joinWith('VehicleImages.Vehicle') 
      ->joinWith('Vehicle.VModel') 
      ->joinWith('Vehicle.VBrand') 
      ->joinWith('Vehicle.CurrrentStatus') 
      ->joinWith('Vehicle.VehicleMode') 
      ->filterByVehicle($filter_avl) 
      ->filterByVehicle($filter_modelAvl) 
      ->filterByVehicle($filter_bndAvl) 
      ->filterByVehicle($filter_cStatus) 
      ->filterByVehicle($filter_mode) 
      ->find(); 
     return $find_vehicles; 
    }//no errors with this code retrieve data perfectly.. Pagination part is the problem.

来源

2015-07-12 PereraSH

请添加关于哪一行导致错误的信息 – canton7

使用'@foreach（$ paginator-> getCollection（）作为$ pg）'而不是'@foreach （$ paginator-> getCollection（） - > all（）as $ pg）' –

我想形成'{{$ pg-> ImagePath}}'这一行。如果我编码为'{{$ pg-> getImagePath（）}}'它给了我错误：调用数组上的成员函数getImagePath（）。 – PereraSH

而不是使用推动我以前照亮的\ Support \外立面\ DB这种情况

$find_vehicles = DB::table('vehicle_images') 
      ->join('vehicle', 'vehicle_images.vehicle_id', '=', 'vehicle.id') 
      ->join('V_model', function ($join1) { 
       $join1->on('vehicle.V_model_id', '=', 'V_model.id')->where('V_model.availability', '=', true); 
      }) 
      ->join('V_brand', function ($join2) { 
       $join2->on('vehicle.V_brand_id', '=', 'V_brand.id')->where('V_brand.availability', '=', true); 
      }) 
      ->join('Currrent_status', 'vehicle.Currrent_status_id', '=', 'Currrent_status.id') 
      ->join('vehicle_transmission', 'vehicle.vehicle_transmission_id', '=', 'vehicle_transmission.id') 
      ->join('vehicle_mode', function ($join3) use($val) { 
       $join3->on('vehicle.vehicle_mode_id', '=', 'vehicle_mode.id')->where('vehicle_mode.mode_name', '=',$val); 
      }) 
      ->paginate(6);

的

如果有任何一个找到方法与推动请发布答案..任何方式谢谢你的人，感谢你的帮助...

来源

2015-07-12 22:25:26 PereraSH

Paginate使用Laravel 5和Propel ORM

回答

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