我正在编程一个应用程序,它应该去一个按钮按下另一个视图控制器,但相反,它崩溃时,我运行它。编辑器显示:并带有编辑器突出显示:但在控制台中没有错误。 Here is the code for the viewcontroller that does the segue: //
// DoTodayViewController.swift
// Paley Foundation: Starfish
我有一个UIpicker模态窗口。一切工作正常,除了一件事。当用户单击输入文本字段时,带有UIpickerView的模式窗口按预期打开。如果所选的行是正确的,并且用户单击确定按钮,则当前代码无法注册该值。 // Set the default row, so if user click ok without changing it is recorded
self.picker.selectRo
This is NOT a duplicate of In Swift, how can I declare a variable of a specific type that conforms to one or more protocols? . This question is about a specific use case where I needed a metatype and
我从CocoaPods安装Google地图SDK后出现此错误。 CoreData: annotation: Failed to load optimized model at path '/Users/nabeel/Library/Developer/CoreSimulator/Devices/96078737-8063-4BC1-97DB-7FECEC6835D9/data/Containers