下面我有此查询: Select b.b_id as Business_id, b.business_name, Average_Rating, b.review_count AS Review_count
FROM (
SELECT b.b_id AS Business_id, AVG(r.rating) AS Average_Rating
FROM Business b
这里是我的SQL小提琴:http://sqlfiddle.com/#!4/75ab7/2 基本上,我创建了一个表,并插入一些数据吧。 CREATE TABLE subject (
id INT NOT NULL,
seq_num INT NOT NULL,
name VARCHAR(30) NOT NULL
);
INSERT INTO subject
Student Name Subject Name Marks
Sam Maths 100
Tom Maths 80
Sam Physical Science 80
John Maths 75
Sam Life Science 70
John Life Science 100
John Physical Scien