2016-07-19 124 views
0

我有两个表products_description与主键​​和第二个表orders_products与外键​​链接这两个表。我们可以说一个产品可以有很多订单。Laravel与雄辩的关系

我为这两个表格创建了以下模型。

namespace App; 

use Illuminate\Database\Eloquent\Model; 

class products_description extends Model 
{ 
    protected $table = "products_description"; 
    protected $primaryKey = "products_id"; 

    public function orders_products() 
    { 
    return $this->belongsTo('App\Orders_product','products_id','products_id'); 
    return $this->hasMany(Orders_product::class); 
    } 
} 

namespace App; 

use Illuminate\Database\Eloquent\Model; 

class Orders_product extends Model 
{ 
    protected $primaryKey = "orders_products_id"; 
} 

在我的控制器类下面的代码

class products_controller extends Controller 
{ 
    public function show1(Products_description $Products_description) 
    { 
    return view('products.show',compact('Products_description')); 
    } 
} 

我show.blade.php文件下面的代码

@extends('layout') 

@section('content') 

{{ $Products_description->products_name }} 

@foreach($Products_description->orders_products as $Orders_product) 
    {{ $Orders_product->orders_id }} 
@endforeach 

@stop 

,我想先显示产品名称然后是该产品所在的订单ID。但是我收到以下错误。没有foreach循环,产品名称显示正常。

试图让非对象的属性(查看:C:\ WAMP \ WWW \ laravel1 \资源\意见\产品\ show.blade.php)

in 0bb3f93ed324818ac22ad70d47add00a1c4f8a7c.php line 11 
at CompilerEngine->handleViewException(object(ErrorException), '1') in PhpEngine.php line 44 
at PhpEngine->evaluatePath('C:\wamp\www\laravel1\storage\framework\views/0bb3f93ed324818ac22ad70d47add00a1c4f8a7c.php', array('__env' => object(Factory), 'app' => object(Application), 'errors' => object(ViewErrorBag), 'Products_description' => object(products_description))) in CompilerEngine.php line 59 
at CompilerEngine->get('C:\wamp\www\laravel1\resources\views/products/show.blade.php', array('__env' => object(Factory), 'app' => object(Application), 'errors' => object(ViewErrorBag), 'Products_description' => object(products_description))) in View.php line 149 

回答

0

我想通了,我用两个关系belongsTohasMany在我products_description模型和我hasMany关系不使用foreign_keylocal_key。其实是问题。我删除了belongsTo关系并添加了foreign_keylocal_keyhasMany的关系,它的工作就像一个魅力。

0

第一这个函数有两种回报,应该删除第一个:

public function orders_products() 
{ 
    return $this->belongsTo('App\Orders_product','products_id','products_id'); 
    return $this->hasMany(Orders_product::class); 
} 

然后在你的控制器功能:

public function show1(Products_description $Products_description) 
{ 
    return view('products.show',compact('Products_description')); 
} 

你不能只是compact('Products_description'),因为它是一个实例。

public function show1(Products_description $Products_description) 
{ 
    $products = $Products_description->all(); 
    return view('products.show',compact('products')); 
} 

上面是你需要什么,或者只是$products = $Products_description->find($productID);

+0

通过从模型中删除第一行,它会在'where子句中给出以下错误Unknown列'orders_products.products_description_id'。因为Laravel或Eloquent尝试从表名中获取主键和外键,所以我们如何定义与表名不同的主键和外键。 – Murtaza

+0

其次,我已经使用'路径模型绑定'和'类型提示',我可以使用compact('Products_description'),它能够在show.blade.php上成功显示产品名称,并且看起来不是这个原因错误。 – Murtaza