我想创建一个搜索函数,所以用户可以通过使用键值进行搜索,但是试图使用的方法返回类型不匹配,已经取出不必要的代码并显示什么是需要。我如何设定积分来接受一个Int而不是“Any”?斯卡拉类型不匹配映射
“键入任何不符合类型为int”
val mapdata = readFile("data.txt")
def handleTwo(): Boolean = {
mnuShowPointsForTeam(currentPointsForTeam)
true
}
def mnuShowPointsForTeam(f: (String) => (String, Int)) = {
print("Team>")
val data = f(readLine)
println(s"${data._1}: ${data._2}")
}
def currentPointsForTeam(team: String): (String, Int) = {
val points = mapdata.get(team) match{
case Some(p) => p
case None => 0
}
(team, points)
}
的data.txt中
SK1, 9, 7, 2, 0, 7, 3, 7, 9, 1, 2, 8, 1, 9, 6, 5, 3, 2, 2, 7, 2, 8, 5, 4, 5, 1, 6, 5, 2, 4, 1
SK2, 0, 7, 6, 3, 3, 3, 1, 6, 9, 2, 9, 7, 8, 7, 3, 6, 3, 5, 5, 2, 9, 7, 3, 4, 6, 3, 4, 3, 4, 1
SK4, 2, 9, 5, 7, 0, 8, 6, 6, 7, 9, 0, 1, 3, 1, 6, 0, 0, 1, 3, 8, 5, 4, 0, 9, 7, 1, 4, 5, 2, 8
SK5, 2, 6, 8, 0, 3, 5, 5, 2, 5, 9, 4, 5, 3, 5, 7, 8, 8, 2, 5, 9, 3, 8, 6, 7, 8, 7, 4, 1, 2, 3
SK6, 2, 7, 5, 9, 1, 9, 8, 4, 1, 7, 3, 7, 0, 8, 4, 5, 9, 2, 4, 4, 8, 7, 9, 2, 2, 7, 9, 1, 6, 9
SK7, 6, 9, 5, 0, 0, 0, 0, 5, 8, 3, 8, 7, 1, 9, 6, 1, 5, 3, 4, 7, 9, 5, 5, 9, 1, 4, 4, 0, 2, 0
SK8, 2, 8, 8, 3, 1, 1, 0, 8, 5, 9, 0, 3, 1, 6, 8, 7, 9, 6, 7, 7, 0, 9, 5, 2, 5, 0, 2, 1, 8, 6
SK9, 7, 1, 8, 8, 4, 4, 2, 2, 7, 4, 0, 6, 9, 5, 5, 4, 9, 1, 8, 6, 3, 4, 8, 2, 7, 9, 7, 2, 6, 6
mapData是什么类型的? “mnuShowPointsForTeam”的返回值是什么(现在只是printlns)? – Thilo
更新了这个问题,mapdata是一个外部txt文件,是的,它只是printlns团队多数民众赞成密钥值输入@Thilo –
但是什么是'mapData'类型?它是“Map [String,Any]”吗?如果你不能创建'Map [String,Int]',那么你必须在这个'case Some(p)'部分内部转换/转换为Int。 – Thilo