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我正在使用SQL Server。我试图进入一个别名字段,作为一个占位符(还没有收到这个数据),我不断收到错误。请看下图。如何输入别名并在此字段中输入全部“”?
我不知道如何在SQL服务器中设置的,但在访问它仅仅是这样的:
任何想法如何,我可以使这项工作?
感谢所有。 下面是SQL脚本:
SELECT dbo.Plan_ID_Mapping.[Level 3 Service], dbo.Plan_ID_Mapping.[PLAN ID],
dbo.All_Enteprise_NONProduction_and_Production_Hardware.Application_Systems_Software_ID_CI_ID AS CI_ID,
dbo.All_Enteprise_NONProduction_and_Production_Hardware.Application_Systems_Software_Name_CI_Name AS CI_Name,
dbo.All_Enteprise_NONProduction_and_Production_Hardware.Description_Product_Name, dbo.Service_Taxonomy.[Critical Y/N],
dbo.Service_Taxonomy.[Criticality Rationale], dbo.qry_BE.BE, dbo.qry_BE.Street, dbo.qry_BE.City, dbo.qry_BE.ST, dbo.qry_BE.Zip, dbo.qry_BE.Country,
dbo.qry_BE.O_L, dbo.qry_BE.ENTITY, dbo.qry_BE.Comp_Code
FROM dbo.Plan_ID_Mapping INNER JOIN
dbo.All_Enteprise_NONProduction_and_Production_Hardware ON
dbo.Plan_ID_Mapping.[PLAN ID] = dbo.All_Enteprise_NONProduction_and_Production_Hardware.Plan_Id INNER JOIN
dbo.LocationWorkSpaceByPlanWithAllIn ON
dbo.All_Enteprise_NONProduction_and_Production_Hardware.Plan_Id = dbo.LocationWorkSpaceByPlanWithAllIn.Plan_Id INNER JOIN
dbo.qry_BE ON dbo.LocationWorkSpaceByPlanWithAllIn.Location_ID = dbo.qry_BE.BE INNER JOIN
dbo.Service_Taxonomy ON dbo.Plan_ID_Mapping.[Level 3 Service] = dbo.Service_Taxonomy.[Level 3]
GROUP BY dbo.Plan_ID_Mapping.[Level 3 Service], dbo.All_Enteprise_NONProduction_and_Production_Hardware.Application_Systems_Software_ID_CI_ID,
dbo.All_Enteprise_NONProduction_and_Production_Hardware.Application_Systems_Software_Name_CI_Name, dbo.Plan_ID_Mapping.[PLAN ID],
dbo.All_Enteprise_NONProduction_and_Production_Hardware.Description_Product_Name, dbo.Service_Taxonomy.[Critical Y/N],
dbo.Service_Taxonomy.[Criticality Rationale], dbo.qry_BE.BE, dbo.qry_BE.Street, dbo.qry_BE.City, dbo.qry_BE.ST, dbo.qry_BE.Zip, dbo.qry_BE.Country,
dbo.qry_BE.O_L, dbo.qry_BE.ENTITY, dbo.qry_BE.Comp_Code
我们需要看到你的代码。你的分组是不正确的。 – scsimon
感谢您的代码。上面的屏幕截图中的PACKAGE_ID是什么?它不包含在你的SQL脚本中 – scsimon