是否可以使用“聚合和组合两个查询”组合（结果集）？

Question

Select id,count(*) as totalX FROM my_table WHERE x_factor = 1 GROUP BY id 

结果集：

id  totalX 
--------- -------------- 
     9    34 
     10    6 
     11    21 
     12    3 

Select id,count(*) as totalY FROM my_table WHERE y_factor = 1 GROUP BY id 

结果集2：

id  totalY 
--------- -------------- 
     9    334 
     10    56 
     11    251 
     12    93 

有没有一种方法，我可以做到这一点：

id  totalX  totalY   
--------- -------------- -------------- 
     9    34    334 
     10    6    56 
     11    21    251 
     12    3    93 

我想为Sybase 12.5的解决方案在RHEL 5，我也想知道这是否可能在任何其他数据库系统。

---谢谢你的答案（S） - 基于真/假的，你可以在这两个

Comparing EXECUTION TIME: (For a certain query) 
Query 1: 
Execution Time 61. 
SQL Server cpu time: 6100 ms. SQL Server elapsed time: 12133 ms. 

Query 2: 
Execution Time 53. 
SQL Server cpu time: 5300 ms. SQL Server elapsed time: 12090 ms. 

Query X(1+2): 
Execution Time 84. 
SQL Server cpu time: 8400 ms. SQL Server elapsed time: 21456 ms. 

Answer 1

通过使用CASE/WHEN为列，总结1或0同样的查询......此外，你可以做同样的事情，如果你想在另一列中的某些值的总和......刚刚替补，对于真正的价值，而不是1

select 
     id, 
     sum(CASE WHEN x_factor = 1 THEN 1 ELSE 0 END) as X_Count, 
     sum(CASE WHEN y_factor = 1 THEN 1 ELSE 0 END) as Y_Count 
    from 
     yourTable 
    group by 
     id 

Answer 2

这应该工作：

SELECT id, 
     sum(case when x_factor = 1 then 1 else 0 end) as totalX, 
     sum(case when y_factor = 1 then 1 else 0 end) as totalY 
    FROM my_table 
    WHERE x_factor = 1 
     OR y_factor = 1 
    GROUP BY id 

Answer 3

CASE ... {0 | 1}对于人们来说是一个很好的窍门，但我认为这个问题可能比这更简单。您是否尝试过：

SELECT id, COUNT(x_factor) AS count_x, COUNT(y_factor) AS count_y FROM my_table GROUP BY id