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我有一个ubuntu服务器,我可以使用ssh连接运行python解释器。 我想将解释器链接到我的IDE之一。spyder和远程ssh python intepreter
spyder是否支持远程ssh intepreter?如果不是什么是可能的免费选择?
编辑: 随着spyder的新版本,它似乎有可能连接到远程外壳。 但是当我尝试连接我收到此错误
>>> Traceback (most recent call last):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 973, in create_client_for_kernel
self._create_client_for_kernel(cf, hostname, kf, pw)
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 1007, in _create_client_for_kernel
if not self.kernel_and_frontend_match(cf):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 898, in kernel_and_frontend_match
profile='default')
File "/usr/lib/python2.7/dist-packages/IPython/kernel/connect.py", line 273, in get_connection_info
info = json.loads(info)
File "/usr/lib/python2.7/json/__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode
raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded
Traceback (most recent call last):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 973, in create_client_for_kernel
self._create_client_for_kernel(cf, hostname, kf, pw)
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 1007, in _create_client_for_kernel
if not self.kernel_and_frontend_match(cf):
File "/home/donbeo/Applications/spyder-ide-3.4dev/spyderlib/plugins/ipythonconsole.py", line 898, in kernel_and_frontend_match
profile='default')
File "/usr/lib/python2.7/dist-packages/IPython/kernel/connect.py", line 273, in get_connection_info
info = json.loads(info)
File "/usr/lib/python2.7/json/__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode
raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded
您认为这个功能将在几周内被包含在pip版本中吗? – Donbeo 2014-08-29 09:52:49
@Donbeo没有确切的日期,但从源代码运行spyder非常简单:安装mercurial,克隆存储库并运行python bootstrap.py。 – Quant 2014-08-29 13:22:00
如果您认为这是对您问题的正确答案,请验证答案。 – Quant 2014-08-29 15:49:03