得到URL和非法字符下载的文件路径

Question

string uri = "https://sometest.com/l/admin/ical.html?t=TD61C7NibbV0m5bnDqYC_q"; 

    string filePath = "D:\\Data\\Name"; 

    WebClient webClient = new WebClient(); 
    webClient.DownloadFile(uri, (filePath + "/" + uri.Substring(uri.LastIndexOf('/')))); 

/// filePath + "/" + uri.Substring(uri.LastIndexOf('/')) = "D:\\Data\\Name//ical.html?t=TD61C7NibbV0m5bnDqYC_q" 

Accesing整个（串）uri，一个的.iCal文件将被自动下载...的文件名room113558101.ics（不，这将帮助）。

如何正确获取文件？

Answer 1

您正在以错误的方式构建文件路径，导致文件名无效（ical.html?t=TD61C7NibbV0m5bnDqYC_q）。相反，使用Uri.Segments属性，并使用路径段（这将是在这种情况下ical.html另外，不要用手合并文件路径 - 使用Path.Combine：

var uri = new Uri("https://sometest.com/l/admin/ical.html?t=TD61C7NibbV0m5bnDqYC_q"); 
var lastSegment = uri.Segments[uri.Segments.Length - 1]; 
string directory = "D:\\Data\\Name"; 
string filePath = Path.Combine(directory, lastSegment); 
WebClient webClient = new WebClient(); 
webClient.DownloadFile(uri, filePath); 

回答您关于得到正确的文件名编辑的问题。在这种情况下，你不知道正确的文件名，直到您对服务器的请求，并得到响应文件名会被包含在响应的Content-Disposition头所以，你应该做的是这样的：。

var uri = new Uri("https://sometest.com/l/admin/ical.html?t=TD61C7NibbV0m5bnDqYC_q"); 
string directory = "D:\\Data\\Name"; 
WebClient webClient = new WebClient(); 
// make a request to server with `OpenRead`. This will fetch response headers but will not read whole response into memory   
using (var stream = webClient.OpenRead(uri)) { 
    // get and parse Content-Disposition header if any 
    var cdRaw = webClient.ResponseHeaders["Content-Disposition"]; 
    string filePath; 
    if (!String.IsNullOrWhiteSpace(cdRaw)) { 
     filePath = Path.Combine(directory, new System.Net.Mime.ContentDisposition(cdRaw).FileName); 
    } 
    else { 
     // if no such header - fallback to previous way 
     filePath = Path.Combine(directory, uri.Segments[uri.Segments.Length - 1]); 
    } 
    // copy response stream to target file 
    using (var fs = File.Create(filePath)) { 
     stream.CopyTo(fs); 
    } 
}