if/else语句中的错误MySQL

-2

我需要一些帮助，使if/else语句在mysql中工作 if语句正常工作，但else语句错误。我的browers告诉我if/else语句中的错误MySQL

“解析错误：在/var/www/domane/public_html/app/save.php线48上的语法错误，意想不到的‘其他’（T_ELSE）” - 这是其他行

它应该得到该行的当前值，然后将其添加到新的值，并更新

<?php 

$dsn = "databasename"; 
$username="username"; 
$password="password"; 

try { 
    $conn = new PDO($dsn, $username, $password); 
    $conn ->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
} catch(PDOException $e) { 
    echo "Connection failed: ".$e->getMessage(); 
} 

//------------------------ Does the category already exist in dietTbl? ------------------------- 
$sql="SELECT COUNT(*) AS subjectcount FROM dietTbl WHERE day=CURDATE()"; 

try { 
          $st = $conn->prepare($sql); 
          $st->bindValue(":mainsubject",$mainSubject, PDO::PARAM_STR); 
          $st->execute(); 
          $row=$st->fetch(); 
          $subjectcount=$row["subjectcount"]; // if >0 the yes, the category already exists 
} catch (PDOException $e) { 
          echo "Server Error - try again!".$e->getMessage(); 
}; 

//------------------------ If it dosn't, insert it into dietTbl ------------------------- 
if ($subjectcount==0) { 

$sql="INSERT INTO dietTbl (day, vegetables, fullgrain, milk, water) values (:day, :vegetables, :fullgrain, :milk, :water)"; 

try { 

    $st = $conn->prepare($sql); 
    $st->bindValue(":day",$_POST["day"], PDO::PARAM_STR); 
    $st->bindValue(":vegetables",$_POST["vegetables"], PDO::PARAM_STR); 
    $st->bindValue(":fullgrain",$_POST["fullgrain"], PDO::PARAM_STR); 
    $st->bindValue(":milk",$_POST["milk"], PDO::PARAM_STR); 
    $st->bindValue(":water",$_POST["water"], PDO::PARAM_STR); 

    $st->execute(); 
          } catch (PDOException $e) { 
                  echo "Server Error - try again!".$e->getMessage(); 
          } 
}; 

//------------------------ If it already exists, update dietTbl ------------------------- 
else { 

SELECT SUM(vegetables) AS totalvegetables, SUM(fullgrain) AS totalfullgrain, SUM(milk) AS totalmilk, SUM(water) AS totalwater FROM dietTbl 



    $sql="UPDATE INTO dietTbl (vegetables, fullgrain, milk, water) values (:vegetables+totalvegetables, :fullgrain+totalfullgrain, :milk+totalmilk, :water+totalwater)"; 

try { 

    $st = $conn->prepare($sql); 
    $st->bindValue(":vegetables",$_POST["vegetables"], PDO::PARAM_STR); 
    $st->bindValue(":fullgrain",$_POST["fullgrain"], PDO::PARAM_STR); 
    $st->bindValue(":milk",$_POST["milk"], PDO::PARAM_STR); 
    $st->bindValue(":water",$_POST["water"], PDO::PARAM_STR); 
    $st->execute(); 
          } catch (PDOException $e) { 
                  echo "Server Error - try again!".$e->getMessage(); 
          } 




}; 

echo "Information saved"; 
$conn=null; //Close database connection 

?>

来源

2015-10-05 Christoffer

之前删除';'在线。 – Jens

谢谢。摆脱了那个错误。这是存储现有值的正确方法吗？因为如果看起来不起作用“SELECT SUM（蔬菜）AS totalvegetables，SUM（fullgrain）AS totalfullgrain，SUM（milk）AS totalmilk，SUM（water）AS totalwater FROM dietTbl ” – Christoffer

已在代码中看到太多错误在进行第一次修复之前删除;从第24，45，71 – rocky

从这部分代码：

}; 

//------------------------ If it already exists, update dietTbl ---------- 

else {

删除“;”

来源

2015-10-05 11:11:40

已经在评论中提到 – rocky

if/else语句中的错误MySQL

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