Question

我希望任何人都可以帮我解决一个小问题。得到一个清晰的头脑后，我仍然坚持，并找不到解决方案。我想这显然很简单。

我坚持一个数组结构，并需要对它们进行排序。下面是该阵列的一个小例子：

$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

可能有BRAND_N正量和n SUB_BRAND_N量。

我有一个订单ID，其stucks一个灵活的订单：

0 = out as in (dont worry about this, catch it at an earlier stage) 
1 = BRAND_1.SUB_BRAND_1 
2 = BRAND_1.SUB_BRAND_2 
3 = BRAND_2.SUB_BRAND_1 

此被延长，如果有更多的这四种情况以及本身可能更改顺序。所以我必须使用这些ID。

顺序应改变阵列中的位置和ID的值推到顶部阵列中，例如：

订单ID = 2：

$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

顺序ID = 3：

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 

---

我至今尝试过这样的：

<?php 

$order[1] = 'BRAND_1::SUB_BRAND_1'; 
$order[2] = 'BRAND_1::SUB_BRAND_2'; 
$order[3] = 'BRAND_2::SUB_BRAND_1'; 

// for testing 
$orderId = 2; 

// get the brand and sub_brand 
$part = explode("::", $order[$orderId]); 

// set the new brand list 
$newBrand[$part[0]]['name'] = $brand[$part[0]]['name']; 
$newBrand[$part[0]]['list'][$part[1]] = $brand[$part[0]]['list'][$part[1]]; 

// unset the brand which should be first of the main brand array 
unset($brand[$part[0]]['list'][$part[1]]); 

// if there was only one list unset the whole brand part 
if(count($brand[$part[0]]['list']) < 1) { 
    unset($brand[$part[0]]); 
} 

现在我有两个数组：

$品牌包括整个品牌，除了这一个应该是第一

$ newBrand只包括该品牌这应该是在顶部

现在我只需要添加$品牌$ newBrand但有我的问题:) 尝试了很多不同的方式重建数组推动内容，替换或合并... b我总是用圈子跑。

任何其他的想法，更短的代码，更好的方法..？

我写的整个代码为codepad.org更好的测试： Codepad example

赞赏任何帮助或建议。

干杯！

编辑：

很抱歉的误解：

顺序是代码以外的规范。目标是根据orderId将一个元素设置为$ brand数组中的顶部。 $ orderId将通过POST，GET或类调用传递。

$ order数组只是一个数组，它可以帮助我在代码中访问规范。

所以$ orderId匹配$ order数组的一个元素，并返回这个元素，它应该位于$ brand数组的顶部。由于没有数字键，我决定使用“brand :: sub_brand”语法来访问这两个深度级别。

希望这解释它更好地litte。

感谢

Answer 1

这里是一个可能的解决方案（测试here）：

<?php 

function getOrderingRules() 
{ 
    return array(
     1 => 'BRAND_1.SUB_BRAND_1', 
     2 => 'BRAND_1.SUB_BRAND_2', 
     3 => 'BRAND_2.SUB_BRAND_1', 
    ); 
} 

function getOrderedBrands($brands, $orderId) 
{ 
    $rules = getOrderingRules(); 
    if (!isset($rules[$orderId])) { 
     throw new RuntimeException("Rule for order id '$orderId' is not specified"); 
    } 

    $result = array(); 

    // Push the first element 
    list($key, $subkey) = explode('.', $rules[$orderId]); 
    $result[$key] = array(
     'name' => $brands[$key]['name'], 
     'list' => array(
      $subkey => $brands[$key]['list'][$subkey], 
     ), 
    ); 

    // Push remaining elements in the order they appear in $rules 
    foreach ($rules as $oid => $rule) { 
     // Skip order id of the first element 
     if ($oid == $orderId) { 
      continue; 
     } 
     list($key, $subkey) = explode('.', $rules[$oid]); 
     if (!isset($result[$key])) { 
      $result[$key] = array(
       'name' => $brands[$key]['name'], 
       'list' => array(), 
      ); 
     } 
     $result[$key]['list'][$subkey] = $brands[$key]['list'][$subkey]; 
    } 

    return $result; 
} 

// Loading all brands (could be external source, like database) 
$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

// Sort and output 
print_r(getOrderedBrands($brand, 1)); 
print_r(getOrderedBrands($brand, 2)); 
print_r(getOrderedBrands($brand, 3)); 

你应该知道，这种阵列结构（$brands），您将无法设置排序规则一样这样的：

1 = BRAND_1.SUB_BRAND_1 
2 = BRAND_2.SUB_BRAND_1 
3 = BRAND_1.SUB_BRAND_2 

，因为一旦你遇见元素通过BRAND_1键，您必须遍历所有的它的子品牌。如果你没有这样的规则，一切都很好。否则，你必须存储有序阵列结构是这样的（因为实际上要排序的子品牌，而不是品牌）：

$subBrands = array(
    array(
     'name' => 'Headline Subbrand 1', 
     'text' => 'Text for it', 
     'parent' => 'BRAND_1', 
     'key' => 'SUB_BRAND_1', 
    ), 
    array(
     'name' => 'Headline Subbrand 2', 
     'text' => 'Text for it', 
     'parent' => 'BRAND_1', 
     'key' => 'SUB_BRAND_2', 
    ), 
); 
$parentBrands = array(
    'BRAND_1' => 'Brand Name 1', 
    'BRAND_2' => 'Brand Name 2', 
); 

然后你就可以排序$subBrands和遍历它