如果条件没有执行

Question

我想弄清楚我的对象是否被打了一点点宽容。但它不起作用。这里是我的代码：

public boolean isClicked(float x) { 

    if (Gdx.input.isTouched() && Gdx.graphics.getHeight() - Gdx.input.getY() >= this.getY() && Gdx.graphics.getHeight() - Gdx.input.getY() <= this.getY() + this.getHeight() && this.getWidth() >= Gdx.input.getX() && x < this.getY() + this.getHeight() * 1.2f && x > this.getY() - this.getHeight() * .2f) { 
     return true; 
    } 

    return false; 

Answer 1

总是试图以这种方式使用条件和使用托架多个条件：

if (Gdx.input.isTouched() && ((Gdx.graphics.getHeight() - Gdx.input.getY()) >= this.getY()) && ((Gdx.graphics.getHeight() - Gdx.input.getY()) <= (this.getY() + this.getHeight())) && (this.getWidth() >= Gdx.input.getX()) && (x < ((this.getY() + this.getHeight()) * 1.2f)) && (x > ((this.getY() - this.getHeight()) * .2f))) { 
     return true; 
} 
return false; 

Answer 2

你应该尝试和格式长线可读性和使用括号。

if (Gdx.input.isTouched() 
    && (Gdx.graphics.getHeight() - Gdx.input.getY()) >= this.getY() 
    && (Gdx.graphics.getHeight() - Gdx.input.getY()) <= (this.getY() + this.getHeight()) 
    && this.getWidth() >= Gdx.input.getX() 
    && x < (this.getY() + this.getHeight() * 1.2f) 
    && x > (this.getY() - this.getHeight() * .2f) 
    ) { 
    return true; 
} 

这也让您注释掉的任何中间行的开头（如使用//）隔离问题。