我试图做一个职位与翻新检查是否有一些数据存在于服务器中。我的问题是,无论如何都要通过onResponse或OnFailure。代码从未传入这两种方法。我在日志中没有出现任何错误。如果我调试,代码到此为止:call.enqueue(新的回调(),并在下一步走法外Post方法与改造永不触发在OnResponse或在OnFailure
一些帮助将欣赏
代码:
ApiInterface apiService = ApiClient.getClient().create(ApiInterface.class);
Call<User> call = apiService.smsPincodeCheck(getPhoneNuber, email);
call.enqueue(new Callback<User>() {
@Override
public void onResponse(Call<User> call, Response<User> response) {
if(response.isSuccess()){
Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
}
if(response.code() == 401){
Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
}
}
@Override
public void onFailure(Call<User> call, Throwable t) {
}
});
接口:
@FormUrlEncoded
@POST("api/check")
Call<User> smsPincodeCheck(@Field("email") String email, @Field("phoneNumber") String phoneNumber);
用户模型:
public class User implements Serializable {
private final static String TAG = "User";
@SerializedName("user")
@Expose
private Long id;
private Long commerceId;
private String email;
private String name;
private String lastname;
private String dni;
private String companyCharge;
.
.
. Getters and setters
JSON:
这是我试图发送到服务器的JSON:
{
"phoneNumber" : "444444444",
"email" : "[email protected]"
}
编辑1:
Call<ResponseSMS> call = apiService.smsPincodeCheck(getPhoneNuber, email);
call.enqueue(new Callback<ResponseSMS>() {
@Override
public void onResponse(Call<ResponseSMS> call, Response<ResponseSMS> response) {
if(response.isSuccess()){
Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
}
if(response.code() == 401){
Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
}
}
@Override
public void onFailure(Call<ResponseSMS> call, Throwable t) {
Toast.makeText(RegisterThreeActivity.this, "Failure", Toast.LENGTH_SHORT).show();
}
});
}
接口:
Call<ResponseSMS> smsPincodeCheck(@Field("email") String email, @Field("phoneNumber") String phoneNumber);
型号:
现在0public class ResponseSMS {
public String response;
public int status;
public String getResponse() {
return response;
}
public void setResponse(String response) {
this.response = response;
}
public int getStatus() {
return status;
}
public void setStatus(int status) {
this.status = status;
}
}
你说你要发送JSON,但你的Retorift接口描述您要发送的形式 – Divers
您的Web服务调用后,什么类型的数据要退从服务器?这些数据与'用户'模型有关吗? –
我怎样才能发送与我的界面Json?服务器不返回任何内容。 –