JSONArray不能申请为java.lang.String

Question

我有这样的凌空onResponse：

public void onResponse(String response) { 
    try { 
     JSONArray info = new JSONArray(response); 

     String name = info.getString("name"); 
     String picture = info.getString("picture"); 
     Picasso.with(context).load(picture).into(profile); 
     user_name.setText(name); 


    } catch (JSONException e) { 
     e.printStackTrace(); 
     Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_LONG).show(); 
    } 

} 

问题是("name")和("picture")给我JSONArray不能申请为java.lang.String。

我错过了什么？

编辑：

[{"name":"josh","picture":"http:\/\/192.168.0.11\/pic.png"}] 

Answer 1

请在解析这个响应！

try { 
      JSONArray info = new JSONArray(response); 

      for (int i =0; i<info.length() ; i++) { 
       JSONObject obj = info.getJSONObject(i); 
       String name = obj.getString("name"); 
       String picture = obj.getString("picture"); 
       Picasso.with(context).load(picture).into(profile); 
       user_name.setText(name); 
      } 


     } catch (JSONException e) { 
      e.printStackTrace(); 
      Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_LONG).show(); 
     } 

Answer 2

扩大对@Atef野兔的评论：

JSONArray info = new JSONArray(response); 

String name = info.getJSONObject(0).getString("name"); 
String picture = info.getJSONObject(0).getString("picture"); 
Picasso.with(context).load(picture).into(profile); 
user_name.setText(name); 

Answer 3

更改下面的代码。

try { 
    JSONArray info = new JSONArray(response); 

    String name = info.getJSONObject(0).getString("name"); 
    String picture = info.getJSONObject(0).getString("picture"); 
    Picasso.with(context).load(picture).into(profile); 
    user_name.setText(name); 


} catch (JSONException e) { 
    e.printStackTrace(); 
    Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_LONG).show(); 
}