我有一个存储过程(MSSQL 2K5),将采取一个变量的LIKE圣诞老人像这样使用变量:在SQL LIKE语句
DECLARE @SearchLetter2 char(1)
SET @SearchLetter = 't'
SET @SearchLetter2 = @SearchLetter + '%'
SELECT *
FROM BrandNames
WHERE [Name] LIKE @SearchLetter2 and IsVisible = 1
--WHERE [Name] LIKE 't%' and IsVisible = 1
ORDER BY [Name]
不幸的是,目前这条线抛出一个语法错误,而评论where子句运行得很好。任何人都可以帮助我得到未评论的行工作?
感谢。它为我工作 – Goldfish 2017-08-26 18:16:12